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我正在尝试使用 sql cmd 执行具有以下内容的 sql 文件。

sqlcmd -S localhost\dbInstance -i Sample.sql -v  filepath="C:\Sql\"

Sample.sql 内容:

USE Sample_db
GO
BEGIN
 BEGIN TRANSACTION; 
  BEGIN TRY
   CREATE VIEW [dbo].[Test_View]
   AS SELECT * from Sample_table;   

   ALTER VIEW [dbo].[Sample_View]   
   AS SELECT * FROM table_9;        

   ALTER TABLE [Sample_Table_2] ADD Col_4 VARCHAR(20);

  END TRY 
 BEGIN CATCH     
  SELECT  ERROR_NUMBER() AS ErrorNumber         ,
    ERROR_SEVERITY() AS ErrorSeverity         ,
    ERROR_STATE() AS ErrorState         ,
    ERROR_PROCEDURE() AS ErrorProcedure         ,
    ERROR_LINE() AS ErrorLine         ,
    ERROR_MESSAGE() AS ErrorMessage;     

  IF @@TRANCOUNT > 0         
   ROLLBACK TRANSACTION; 

 END CATCH;

 IF @@TRANCOUNT > 0     
  COMMIT TRANSACTION;

END  
GO

当我执行 sqlcmd 时,它会引发以下错误:

C:\Sql>sqlcmd -S localhost\dbInstance -i Sample.sql -v  filepath="C:\Sql\"
Changed database context to 'Sample_db'.
Msg 156, Level 15, State 1, Server localhost\dbInstance, Line 5
Incorrect syntax near the keyword 'VIEW'.

问题: 为什么我不能从 sqlcmd 创建视图和更改视图,而我可以更改表?当我注释掉 CREATE VIEW 和 ALTER VIEW 语句时,脚本执行得很好。

谢谢!

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1 回答 1

9
于 2012-05-06T00:12:05.877 回答