python - Python中的回文

Question

fno = input()
myList = list(fno)
sum = 0
for i in range(len(fno)):
    if myList[0:] == myList[:0]:
    continue
print (myList)

我想做一个数字回文。例如：

input(123)
print(You are wrong)
input(12121)
print(you are right) 

请指导我如何在 python 中制作回文。它不完整的代码请建议我下一步做什么。

谢谢

Answer 1

我想，给定您的代码，您想检查回文，而不是制作回文。

您的代码存在许多问题，但简而言之，它可以减少到

word = input()
if word == "".join(reversed(word)):
    print("Palidrome")

让我们谈谈你的代码，这没有多大意义：

fno = input() 
myList = list(fno) #fno will be a string, which is already a sequence, there is no need to make a list.
sum = 0 #This goes unused. What is it for?
for i in range(len(fno)): #You should never loop over a range of a length, just loop over the object itself.
    if myList[0:] == myList[:0]: #This checks if the slice from beginning to the end is equal to the slice from the beginning to the beginning (nothing) - this will only be true for an empty string.
        continue #And then it does nothing anyway. (I am presuming this was meant to be indented)
print (myList) #This will print the list of the characters from the string.

Answer 2

切片符号在这里很有用：

>>> "malayalam"[::-1]
'malayalam'
>>> "hello"[::-1]
'olleh'

请参阅解释 Python 的切片表示法以获得很好的介绍。

Answer 3

str=input('Enter a String')
print('Original string is : ',str)
rev=str[::-1]
print('the reversed string is : ',rev)
if(str==rev):
    print('its palindrome')
else:
    print('its not palindrome')

Answer 4

x=raw_input("enter the string")
while True:
    if x[0: ]==x[::-1]:
        print 'string is palindrome'
        break
    else:
        print 'string is not palindrome'
        break