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我正在研究 ASmack。使用 asmack 获取聊天室用户列表是否可行? http://www.igniterealtime.org/builds/smack/docs/latest/documentation/extensions/muc.html 此列表未显示。请给我一些想法。

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3 回答 3

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Which list?

You can only call getOccupants() if you are an occupant of the MUC or, in other words, if have joined the MUC.

于 2012-05-05T10:26:44.333 回答
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getOc​​cupants()对我不起作用。所以你可以试试下面的代码:

 try {         
       ServiceDiscoveryManager discoManager =  ServiceDiscoveryManager.getInstanceFor(xmppConn);
       DiscoverItems discoItems = discoManager.discoverItems(roomJID);
       Iterator<DiscoverItems.Item> occupants = discoItems.getItems();  

     } catch (XMPPException e) {
       e.printStackTrace();                
     }
于 2014-01-22T18:18:28.627 回答
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通过将参数作为 MultiUserChat 对象传递的简单跟随方法,我能够获取 XMPP 聊天室中可用的用户列表。

public static List<String> findMulitUser(MultiUserChat muc) {
    List<String> listUser = new ArrayList<String>();
    Iterator<String> it = muc.getOccupants();
    // Traverse the chat room name
    while (it.hasNext()) {
        // Chat room members name
        String name = StringUtils.parseResource(it.next());
        System.out.println("Name Of Occupants------>" + name);
        listUser.add(name);
    }
    return listUser;
}
于 2015-04-11T13:09:59.017 回答