45

在我的应用程序中，我需要录制视频。在开始录制之前，我为其分配了名称和目录。录制完成后，用户可以重命名他的文件。我写了以下代码，但似乎它不起作用。

当用户输入文件名并单击按钮时，我会这样做：

private void setFileName(String text) {     
        String currentFileName = videoURI.substring(videoURI.lastIndexOf("/"), videoURI.length());
        currentFileName = currentFileName.substring(1);
        Log.i("Current file name", currentFileName);

        File directory = new File(Environment.getExternalStoragePublicDirectory(Environment.DIRECTORY_MOVIES), MEDIA_NAME);
        File from      = new File(directory, "currentFileName");
        File to        = new File(directory, text.trim() + ".mp4");
        from.renameTo(to);
        Log.i("Directory is", directory.toString());
        Log.i("Default path is", videoURI.toString());
        Log.i("From path is", from.toString());
        Log.i("To path is", to.toString());
    }

文本：是用户输入的名称。当前文件名：是我在录制之前分配的名称 MEDIA_NAME：文件夹名称

Logcat 显示了这一点：

05-03 11:56:37.295: I/Current file name(12866): Mania-Karaoke_20120503_115528.mp4
05-03 11:56:37.295: I/Directory is(12866): /mnt/sdcard/Movies/Mania-Karaoke
05-03 11:56:37.295: I/Default path is(12866): /mnt/sdcard/Movies/Mania-Karaoke/Mania-Karaoke_20120503_115528.mp4
05-03 11:56:37.295: I/From path is(12866): /mnt/sdcard/Movies/Mania-Karaoke/currentFileName
05-03 11:56:37.295: I/To path is(12866): /mnt/sdcard/Movies/Mania-Karaoke/hesam.mp4

任何建议将不胜感激。

4

9 回答 9

60

在您的代码中：

不应该是：

File from = new File(directory, currentFileName);

代替

File from = new File(directory, "currentFileName");

为了安全，

使用 File.renameTo() 。但是在重命名之前检查目录是否存在！

File dir = Environment.getExternalStorageDirectory();
if(dir.exists()){
    File from = new File(dir,"from.mp4");
    File to = new File(dir,"to.mp4");
     if(from.exists())
        from.renameTo(to);
}

参考：http: //developer.android.com/reference/java/io/File.html#renameTo%28java.io.File%29

于 2012-05-03T04:17:00.467 回答
23

问题出在这一行，

File from = new File(directory, "currentFileName");

这currentFileName实际上是一个您不必使用的字符串"

试试这个方法

File from      = new File(directory, currentFileName  );
                                    ^               ^         //You dont need quotes
于 2012-05-03T04:24:10.603 回答
13

使用此方法重命名文件。该文件from将重命名为to.

private boolean rename(File from, File to) {
    return from.getParentFile().exists() && from.exists() && from.renameTo(to);
}

示例代码：

public class MainActivity extends Activity {
    private static final String TAG = "YOUR_TAG";

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        File currentFile = new File("/sdcard/currentFile.txt");
        File newFile = new File("/sdcard/newFile.txt");

        if (rename(currentFile, newFile)) {
            //Success
            Log.i(TAG, "Success");
        } else {
            //Fail
            Log.i(TAG, "Fail");
        }
    }

    private boolean rename(File from, File to) {
        return from.getParentFile().exists() && from.exists() && from.renameTo(to);
    }
}
于 2015-08-22T11:43:55.527 回答
5 

/**
 * ReName any file
 * @param oldName
 * @param newName
 */
public static void renameFile(String oldName,String newName){
    File dir = Environment.getExternalStorageDirectory();
    if(dir.exists()){
        File from = new File(dir,oldName);
        File to = new File(dir,newName);
         if(from.exists())
            from.renameTo(to);
    }
}
于 2014-06-01T09:07:00.610 回答
3

工作示例...

   File oldFile = new File("your old file name");
    File latestname = new File("your new file name");
    boolean success = oldFile .renameTo(latestname );

   if(success)
    System.out.println("file is renamed..");
于 2014-05-15T06:25:20.647 回答
2

提供具有不同文件名的目标文件对象。

// Copy the source file to target file.
// In case the dst file does not exist, it is created
void copy(File source, File target) throws IOException {

    InputStream in = new FileInputStream(source);
    OutputStream out = new FileOutputStream(target);

    // Copy the bits from instream to outstream
    byte[] buf = new byte[1024];
    int len;

    while ((len = in.read(buf)) > 0) {
        out.write(buf, 0, len);
    }

    in.close();
    out.close();
}
于 2012-05-03T04:13:01.870 回答
1

你应该检查目录是否存在！

File directory = new File(Environment.getExternalStoragePublicDirectory(Environment.DIRECTORY_MOVIES), MEDIA_NAME);
if(!directory.exist()){
    directory.mkdirs();
}
于 2012-05-03T04:15:54.450 回答
1 
public void renameFile(File file,String suffix) {

    String ext = FilenameUtils.getExtension(file.getAbsolutePath());
    File dir = file.getParentFile();
    if(dir.exists()) {
        File from = new File(dir, file.getName());
        String name = file.getName();
        int pos = name.lastIndexOf(".");
        if (pos > 0)
            name = name.substring(0, pos);
        File to = new File(dir, name + suffix + "." + ext);
        if(from.exists())
            from.renameTo(to);
    }

}
于 2018-06-04T17:27:24.837 回答
1

这就是我最终使用的。它通过在文件名中添加一个整数来处理存在同名文件的情况。

@NonNull
private static File renameFile(@NonNull File from, 
                               @NonNull String toPrefix, 
                               @NonNull String toSuffix) {
    File directory = from.getParentFile();
    if (!directory.exists()) {
        if (directory.mkdir()) {
            Log.v(LOG_TAG, "Created directory " + directory.getAbsolutePath());
        }
    }
    File newFile = new File(directory, toPrefix + toSuffix);
    for (int i = 1; newFile.exists() && i < Integer.MAX_VALUE; i++) {
        newFile = new File(directory, toPrefix + '(' + i + ')' + toSuffix);
    }
    if (!from.renameTo(newFile)) {
        Log.w(LOG_TAG, "Couldn't rename file to " + newFile.getAbsolutePath());
        return from;
    }
    return newFile;
}
于 2016-08-30T18:24:11.543 回答