0

我在我目前正在开发的一个应用程序中使用 noty jquery 通知http://needim.github.com/noty/ 。它提供了“确认”功能，但我想在访问者按“确定”时在 php 中执行某些操作，并在访问者按“取消”时执行其他操作。如何将此功能添加到我的脚本中？到目前为止，我的代码（特定段）是以下代码：

<?php
    //add2cart section
if(isset($_POST['add2cart'])){
//$plus1 = +1;
$order_date = date("Y/m/d");
$img_name = $_POST['img_name'];
//$color = $_POST['color'];
$sqldata = "select * from orders where img_name = '$img_name' and 
sess_user = '$user and checkout= ' ' "; 
$dataselect = mysql_query($sqldata);
$sqlnum = mysql_num_rows($dataselect);
if($sqlnum >= 1){?>
    <script type="text/javascript">
noty({"text":"This item is already in your cart. 
Are you sure you want to add it one more time?","layout":"center","type":"confirm","textAlign":"center","easing":"swing","animateOpen":{"height":"toggle"},"animateClose":{"height":"toggle"},"speed":"500",buttons: [
  {type: 'button green', text: 'Ok', click: function($noty) {

      // this = button element
      // $noty = $noty element

      //$noty.close();
      noty({force: true, text: 'You clicked "Ok" button', type: 'success'});
    }
  },
  {type: 'button pink', text: 'Cancel', click: function($noty) {
      //$noty.close();
      noty({force: true, text: 'You clicked "Cancel" button', type: 'error'});
    }
  }
  ],
closable: false,
timeout: false});                        
    </script>
<?php          
}else{?>
    <script type="text/javascript">
        noty({"text":"Item added.","layout":"center","type":"success","textAlign":"center","easing":"swing","animateOpen":{"height":"toggle"},"animateClose":{"height":"toggle"},"speed":"500","timeout":"3000","closable":true,"closeOnSelfClick":true});                        
    </script>
<?php
$sizevalue = '5\" x 7\"(13 x 19 cm)';
$sql_order ="insert into orders(item_id, img_name, quantity, color, order_date, sess_user, size, unique_id) values(' ', '$img_name', '1', 'Color', '$order_date', '$user', '$sizevalue', '$unique_id')";
mysql_query($sql_order);    
}
}
?>

我会很感激任何帮助，谢谢你的时间。

4

1 回答 1

0

您不能直接从 js 执行 PHP，您必须在 click 处理程序的某处执行 ajax 请求。

click: function($noty) {
    // do some ajax
    ...
}
于 2012-05-02T14:55:16.233 回答