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我必须在 iOS 中访问 Rest api，为此我正在使用 RestKit。服务器只接受 POST 请求并以 JSON 格式发送响应。只需帮助我使用 RestKit 调用登录 api。网址是这样的：

http://mobile.domian.co/apiversion/user/login

和 Post 参数是：

app_key(string),signature(string),timestamp(dateTime),user_id(string),password(string)。

可用的响应表示

{
"status": "0",
"result": {
    "error_code": "1",
    "error_msg": "Login failed. Wrong username or password"
}

{“状态”：“1”，“结果”：{“数据”：{“头像”：“”，“电子邮件”：“sd.p@clozette.co”，“用户名”：“sd”，“通讯“：”1，“bio_data”：“关于我自己”，“mth_dob”：“1”，“yr_dob”：“1981”，“hometown”：“”，“dob_priv”：“1”，“hometown_priv”： “1”，“bio_data_priv”：“1”，“block_comment_notification”：“0”，“block_liked_notification”：“0”，}

请帮我。提前致谢。

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1 回答 1

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这是答案（您应该将日期时间转换为字符串）：-

        NSString *post =[NSString stringWithFormat:@"app_key=%@&signature=%@&timestamp=%@&user_id=%@&password=%@",appKEY,Signature,Datetime,UID,Password];

    NSData *postData = [post dataUsingEncoding:NSUTF8StringEncoding allowLossyConversion:YES];

    NSString *postLength = [NSString stringWithFormat:@"%d", [postData length]];

    NSMutableURLRequest *request = [[[NSMutableURLRequest alloc] init] autorelease];
    [request setURL:[NSURL URLWithString:@"Your URL"]];
    [request setHTTPMethod:@"POST"];
    [request setValue:postLength forHTTPHeaderField:@"Content-Length"];
    [request setValue:@"application/x-www-form-urlencoded charset=utf-8" forHTTPHeaderField:@"Content-Type"];
    [request setHTTPBody:postData];

    NSError *error;
    NSURLResponse *response;
    NSData *returnData=[NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error];
    if (error)
{
    NSLog(@"Error is %@",[error localizedDescription]);
}

    returnString=[[NSString alloc]initWithData:returnData encoding:NSUTF8StringEncoding];
    if(!returnString)
    {
        UIAlertView *erroralert = [[UIAlertView alloc] initWithTitle:@"Error" message:@"There is an error getting response" delegate:self cancelButtonTitle:nil otherButtonTitles:@"OK", nil];
        [erroralert show];
        [erroralert release];
    }
    else 
    {
        NSLog(@"%@",returnString);
    }
    SBJSON *json = [[SBJSON new] autorelease];
    NSMutableDictionary *dic = [[NSMutableDictionary alloc] initWithDictionary:[json objectWithString:returnString error:nil]];
于 2012-05-01T14:05:21.840 回答