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我有以下代码，我收到以下错误

错误 C2036：“void *”：未知大小
错误 C2440：“static_cast”：无法从“void *”转换为“size_t”

在线

void *addr = static_cast <void*> (static_cast <size_t> (mem + bytesAlreadyAllocated));

我的问题是为什么我会遇到错误以及如何摆脱这些错误？

感谢帮助。

class MemoryChunk {
public:
    MemoryChunk (MemoryChunk *nextChunk, size_t chunkSize);
    ~MemoryChunk() {delete mem; }

    inline void *alloc (size_t size);
    inline void free (void* someElement);

    // Pointer to next memory chunk on the list.
    MemoryChunk *nextMemChunk() {return next;}
    // How much space do we have left on this memory chunk?
    size_t spaceAvailable() { return chunkSize - bytesAlreadyAllocated; }

    // this is the default size of a single memory chunk.
    enum { DEFAULT_CHUNK_SIZE = 4096 };
private:

    // The MemoryChunk class is a cleaner version of NextOnFreeList. It separates the next pointer from
    // the actual memory used for the allocated object. It uses explicit next and mem pointers, with no 
    // need for casting.

    MemoryChunk *next;
    void *mem;

    // The size of a single memory chunk.
    size_t chunkSize;
    // This many bytes already allocated on the current memory chunk.
    size_t bytesAlreadyAllocated;
};

MemoryChunk::MemoryChunk(MemoryChunk *nextChunk, size_t reqSize) {
    chunkSize = (reqSize > DEFAULT_CHUNK_SIZE) ? reqSize : DEFAULT_CHUNK_SIZE;
    next = nextChunk;
    bytesAlreadyAllocated = 0;
    mem = new char [chunkSize];
}

void* MemoryChunk :: alloc (size_t requestSize) {
    void *addr = static_cast <void*> (static_cast <size_t> (mem + bytesAlreadyAllocated));
    bytesAlreadyAllocated += requestSize;
    return addr;
}

inline void MemoryChunk :: free (void *doomed) {}
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1 回答 1

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表达方式：

static_cast <size_t> (mem + bytesAlreadyAllocated)

使用未定义大小 ( void) 的类型应用偏移量。由于void没有大小，因此程序格式不正确。

char*是适合您在这种情况下使用的指针。例如：

`char* mem;`
 // and
 char* addr(mem + bytesAlreadyAllocated);

更新

所以在下面的程序中：

#include <iostream>

int main(int argc, const char* argv[]) {
    const int array[3] = {-1, 0, 1};
    std::cout << *(array + 0) << ", "
      << *(array + 1) << ", " << *(array + 2) << "\n";
    return 0;
}

输出是-1, 0, 1。元素偏移量是根据数组元素的大小和类型应用的。与void-- 大小不合适。

于 2012-04-30T09:50:19.057 回答