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我有以下对象：

countDictionary As Dictionary(of Category, Dictionary(of Date, Integer))

有Class一个枚举属性。出于演示的目的，我将其称为MasterCategory.

我一直在尝试取出一个如下所示的对象：

groupedCountDictionary As Dictionary(of MasterCategory, Dictionary(of Date, Integer)

我能得到的最好结果是：

Lookup(of MasterCategory, Dictionary(of Date, Integer))

从：

countDictionary.ToLookup(Function(o) o.Key.MasterCategory, Function(o) o.Value)

这导致IEnumerable (Of Dictionary(of Date, Integer))每个MasterCategory值都有一个。

但是，我需要将字典的 IEnumerable 展平为一个字典，其中每个日期的所有整数相加（总计数）。

然后我尝试使用各种selects 和group bys （来自许多 stackoverflow 帖子）来“扁平化”它，但我的努力没有成功。

谁能建议一种方法来做到这一点？如果可能的话，寻找VB.Net的答案。

编辑：

当前代码

[Category Class]
-    MasterCategory As Enum
-    Name As String etc

[countDictionary As Dictionary(of Category Objects, Dictionary(of Date, Integer))]
-    length 8
-    Children of 8 Categories:
        3 with MasterCategory A, 1097 int's by date
        4 with MasterCategory B, 1097 int's by date
        1 with MasterCategory C, 1097 int's by date

最大的努力

[Lookup(of MasterCategory, Dictionary(of Date, Integer)]
-    length 3
-    Children of 3 Master Categories:
     1 of IEnumerable(of Dictionary(of Date, Integer)) and length 3
         3 x Dictionary length 1097 int's by date

     1 of IEnumerable(of Dictionary(of Date, Integer)) and length 4
         3 x Dictionary length 1097 int's by date

     1 of IEnumerable(of Dictionary(of Date, Integer)) and length 1
         3 x Dictionary length 1097 int's by date

必需的

[Dictionary(MasterCategory, Dictionary(of Date, Integer))]
-    length 3
-    Children of 3 Master Categories:
     3 of Dictionary(of Date, Integer) with summed total int's
4

1 回答 1

1

你在追求SelectMany吗？如果是这样，这可能会满足您的需求：

C＃

test.SelectMany(x => x.Key.MasterCategory).Sum(x => x.ThePropertyToSum)

在VB中，我认为是：

test.SelectMany(Function(x) x.Key.MasterCategory).Sum(Function(x) x.ThePropertyToSum)
于 2012-04-16T11:47:01.933 回答