我正在尝试将第一个示例http://www.dotnetperls.com/convert-list-string实现到我的方法中,但我很难匹配该方法的第二个参数:
string printitout = string.Join(",", test.ToArray<Location>);
错误信息:
The best overloaded method match for 'string.Join(string,
System.Collections.Generic.IEnumerable<string>)' has some invalid arguments
所有的 IList 接口也是用 IEnurmerable 实现的(除非有人希望我在此列出)。
class IList2
{
static void Main(string[] args)
{
string sSite = "test";
string sSite1 = "test";
string sSite2 = "test";
Locations test = new Locations();
Location loc = new Location();
test.Add(sSite)
test.Add(sSite1)
test.Add(sSite2)
string printitout = string.Join(",", test.ToArray<Location>); //having issues calling what it needs.
}
}
string printitout = string.Join(",", test.ToArray<Location>);
public class Location
{
public Location()
{
}
private string _site = string.Empty;
public string Site
{
get { return _site; }
set { _site = value; }
}
}
public class Locations : IList<Location>
{
List<Location> _locs = new List<Location>();
public Locations() { }
public void Add(string sSite)
{
Location loc = new Location();
loc.Site = sSite;
_locs.Add(loc);
}
}
编辑:确定使用“string.Join(”,, test);” 工作,在我用复选标记关闭它之前,由于某种原因我的输出,输出:
“Ilistprac.Location,Ilistprac.Location,Ilistprac.Location”
出于某种原因,而不是列表中的内容。