java - 按姓名提取联系电话号码

Question

我试图通过他的名字获取联系人的电话号码，（名字是一个字符串），有人知道怎么做吗？谢谢！

Answer 1

这应该对您有所帮助；将 People.NAME 替换为您想要的名称。

    String[] projection = new String[]{
            People.NAME,
            People.NUMBER
         };

    Cursor c = ctx.getContentResolver().query(People.CONTENT_URI, projection,
    null, null, People.NAME + " ASC");
    c.moveToFirst();
    int nameCol = c.getColumnIndex(People.NAME);
    int numCol = c.getColumnIndex(People.NUMBER);

    int nContacts = c.getCount();
    do{
        // Do your work here
    } while(c.moveToNext());

希望能帮助到你。

Answer 2

应该为你工作。返回分配给此联系人的所有号码的列表

   public static List<String> getContactByName(Context context,
         String name) {
         String[] mProjection = {
               ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME,
               ContactsContract.CommonDataKinds.Phone.CONTACT_ID,
               ContactsContract.CommonDataKinds.Phone.NUMBER };

         Cursor cursor = context.getContentResolver().query(
               ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
               mProjection,
               ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME + " LIKE '%"
                     + name + "%'", null, null);

         List<String> listOfPhonesAssignedToThisName = new ArrayList<String>();
         while(cursor.moveToNext()){
            listOfPhonesAssignedToThisName.add(cursor.getString(cursor.getColumnIndexOrThrow("DISPLAY_NAME")));
         }
         return listOfPhonesAssignedToThisName;
   }

注意：这个函数比较所有看起来像你的显示名称的东西。如果你想找到合适的人，你需要调整部分：

ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME + " LIKE '%" + name + "%'", null, null);

至： ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME + " LIKE '" + name + "'", null, null);