我正在做一个需要检查与第一次发布日期的时差的项目。我正在使用 NSDayCalendarUnit 和 NSWeekCalendarUnit。基本上在前两周的每一天,我都想做一些事情。我正在使用的对象需要一次每两天处于某种状态。
所以例如
Day 1 & 2, Week 0 - State 1
Day 3 & 4, Week 0 - State 2
...
Day 1 & 2, Week 1 - State 8
Day 3 & 4, Week 1 - State 9
这是我的代码:
// get the data/time difference from the first launch
int daysDifferent = [[dateDifferenceInfo objectForKey:@"days"] intValue];
int weeksDifferent = [[dateDifferenceInfo objectForKey:@"weeks"] intValue];
if(daysDifferent == 2 | daysDifferent == 3 && !weeksDifferent && _dot.age != 2){
// set state
}
if(daysDifferent == 4 | daysDifferent == 5 && !weeksDifferent && _dot.age != 3){
// set state
}
if((daysDifferent == 6 && weeksDifferent == 0 | daysDifferent == 0 && weeksDifferent == 1) && _dot.age != 4){
// set state
}
if(daysDifferent == 0 | daysDifferent == 1 && weeksDifferent == 1 && _dot.age != 5){
// set state
}
if(daysDifferent == 2 | daysDifferent == 3 && weeksDifferent == 1 && _dot.age != 6){
// set state
}
if(daysDifferent == 4| daysDifferent == 5 && weeksDifferent == 1 && _dot.age != 7){
// set state
}
if((daysDifferent == 6 && weeksDifferent == 1 | daysDifferent == 0 && weeksDifferent == 2) && _dot.age != 8){
// set state
}
if(weeksDifferent >= 2 && !(daysDifferent % 2)){
// set state
}
旁注:我知道这是不好的代码,我打算用 switch case 替换它,我只需要先进行逻辑排序。
我的问题是有没有更好的方法来计算这种模式?