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使用 Oracle 11G（不是 R2）数据库，我们需要创建显示个人报告结构属于哪个领导委员会的报告。

在高层次上，我们通过在表 board_members 中定位员工 ID 来确定个人在董事会中的存在。

board_members 表有一个职位 ID，可用于访问 board_positions，从那里我们可以确定该职位是否在领导委员会中。（以下示例。）

对于领导委员会中的任何员工，他自己的 ID 将代表 BOARD_LEAD。

对于任何其他员工，report_to 值会递归，直到确定领导委员会成员，并且该人的 ID 将为 BOARD_LEAD。

我们的顶级员工有 report_to 等于他们自己的 empl_id，而不是更常见的 NULL。

为了希望证明这一点，我在下面设置了示例表、示例数据和示例所需的输出。

我正在尝试了解如何创建一个视图，该视图将为全职等效和其他报告需求提供此类信息。我确信将涉及 CONNECT BY，但我发现 Oracle 文档令人困惑，并且我没有找到包含多个表的示例。（我担心缺乏例子是有充分理由的。）

甚至可以在 Oracle 11g（不是 R2）上编写这样的视图，而不是在每次位置更改时都必须更新的中间表？

Create table board_positions /* If board_position = 'LDRSHPCOMM' this is a top position */
(member_id varchar(6),board_position varchar(18));

Create table board_members 
(empl_id varchar(6), member_id varchar(6));

Create table emp 
(empl_id varchar(6),ename varchar(32),report_to varchar(6));

Insert into board_positions values('CEO','LDRSHPCOMM');
Insert into board_positions Values('COO','LDRSHPCOMM');
Insert into board_positions Values('CFO','LDRSHPCOMM');
Insert into board_positions Values('CIO','LDRSHPCOMM');
Insert into board_positions values('WANABE','NEWBIE');

Insert into emp ('TOPDOG','Big Guy','TOPDOG');
Insert into emp ('WALLET','Money Bags','TOPDOG');
Insert into emp ('OPSGUY','Meikut Work','TOPDOG');
Insert into emp ('INFGUY','Comp U Turk','TOPDOG');
Insert into emp ('HITECH','Number 2','INFGUY');
Insert into emp ('LOTECH','Number 3','HITECH');
Insert into emp ('PROGMR','Nameless Blameless','LOTECH');
insert into emp ('FLUNKY','Ida Dunnit','PROGMR');

Insert into board_members ('TOPDOG','CEO');
Insert into board_members ('WALLET','CFO');
Insert into board_members ('OPSGUY','COO');
Insert into board_members ('INFGUY','CIO');
Insert into board_members ('HITECH','WANABE');  /* Board position not on the leadership committee */

使用类似的东西：

CREATE VIEW LEADER_VIEW AS
   WITH T1 AS (SELECT e.empl_id, (something) as board_lead
                , (something) as board_lead_pos
           FROM emp e
           LEFT OUTER JOIN board_members bm
                        ON bm.empl_id = e.empl_id
           LEFT OUTER JOIN board_positions bp
                        on bp.member_id = bm.member_id
           ...
           CONNECT BY PRIOR empl_id = report_to
           START WITH empl_id = report_to
           )
  SELECT * FROM T1

（但我知道它远不止这些！）

所需的输出示例。. .

TOPDOG         TOPDOG  CEO  (Because self is on LDRSHPCOMM)
WALLET         WALLET  CFO  (Because self is on LDRSHPCOMM)
OPSGUY         OPSGUY  COO  (Because self is on LDRSHPCOMM)
INFGUY         INFGUY  CIO  (Because self is on LDRSHPCOMM)
HITECH         INFGUY  CIO  (Because REPORTTO is on LDRSHPCOMM)
LOTECH         INFGUY  CIO  (Because REPORTTO->REPORTTO is on LDRSHPCOMM)
PROGMR         INFGUY  CIO  (REPORTTO->REPORTTO->REPORTTO is on LDRSHPCOMM)
FLUNKY         INFGUY  CIO  (You know by now.)
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1 回答 1

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你可以这样做：

SQL> SELECT *
  2    FROM (SELECT empl_id, ename, report_to,
  3                 member_id, board_position,
  4                 MAX(lvl) over(PARTITION BY empl_id) maxlvl, lvl
  5             FROM (SELECT connect_by_root(e.empl_id) empl_id,
  6                          connect_by_root(e.ename) ename,
  7                          bm.empl_id report_to,
  8                          LEVEL lvl, bp.*
  9                      FROM emp e
 10                      LEFT JOIN board_members bm
 11                             ON e.empl_id = bm.empl_id
 12                      LEFT JOIN board_positions bp
 13                             ON bm.member_id = bp.member_id
 14                    CONNECT BY NOCYCLE e.empl_id = PRIOR e.report_to
 15                           AND (PRIOR bp.board_position IS NULL
 16                                OR PRIOR bp.board_position != 'LDRSHPCOMM')))
 17   WHERE lvl = maxlvl;

EMPL_ID ENAME                            REPORT_TO MEMBER_ID BOARD_POSITION     
------- -------------------------------- --------- --------- ------------------ 
FLUNKY  Ida Dunnit                       INFGUY    CIO       LDRSHPCOMM         
HITECH  Number 2                         INFGUY    CIO       LDRSHPCOMM         
INFGUY  Comp U Turk                      INFGUY    CIO       LDRSHPCOMM         
LOTECH  Number 3                         INFGUY    CIO       LDRSHPCOMM         
OPSGUY  Meikut Work                      OPSGUY    COO       LDRSHPCOMM         
PROGMR  Nameless Blameless               INFGUY    CIO       LDRSHPCOMM         
TOPDOG  Big Guy                          TOPDOG    CEO       LDRSHPCOMM         
WALLET  Money Bags                       WALLET    CFO       LDRSHPCOMM

我没有 START WITH 子句，因为我想为所有员工启动分层查询。对于每个员工，我都会遍历层级数据，直到找到领导委员会的董事会成员（CONNECT BY 子句）。

外部查询过滤相关行。

于 2012-04-11T08:39:48.137 回答