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我无法让 iPhone 应用程序使用我的 API 正确发送 POST。进行调用时，根本不返回任何结果。

  1. POST 调用旨在发送消息（存储消息，检查某些参数，并启动“推送”通知）

  2. post 调用在 .php 文件上的表单中起作用，但在通过应用程序使用时不起作用。返回结果： {"message":{"message":{"saved":1}},"pushed":1,"error":[]} 推送期间的错误是预期的，因为 test2.php 没有发送消息到移动设备，只是数据库。

  3. 这是应用程序的 POST 代码

    NSDate *now = [NSDate date];
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:@"yyyy-MM-dd HH:mm:ss"];
NSString *time = [dateFormatter stringFromDate:now];
NSLog(@"time : %@", time);
NSLog(@"message : %@", self.messageTxt.text);

NSString *urlString = [[Utils getSendMessageUrl] stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:[NSURL URLWithString:urlString]];
[request setHTTPMethod:@"POST"];
[request setValue:[UserSession sharedInstance].customerTableNum forHTTPHeaderField:@"point"];
[request setValue:[UserSession sharedInstance].locationId forHTTPHeaderField:@"location"];
[request setValue:time forHTTPHeaderField:@"sent"];
[request setValue:self.messageTxt.text forHTTPHeaderField:@"message"];
[request setValue:[UserSession sharedInstance].phoneNumber forHTTPHeaderField:@"number"];

self.receivedData = [NSMutableData data];
NSURLConnection *sendConnection = [NSURLConnection connectionWithRequest:request delegate:self];
[sendConnection scheduleInRunLoop:[NSRunLoop currentRunLoop] forMode:NSRunLoopCommonModes];
[sendConnection start];

什么可能导致应用加载 index.php 却没有结果？后变量设置正确，即使“推送”失败，消息仍应输入数据库（因为 test2.php 成功）。

提前感谢您的任何见解。

- - - - - - 编辑 - - - - - - - -

这是我的应用程序开发人员的回复：

pragma mark - NSURLConnection delegate


  (void)connection:(NSURLConnection *)connection didReceiveResponse:(NSURLResponse *)response
 {
     NSLog(@"didReceiveResponse");
     [self.receivedData setLength:0];
 }

 (void)connection:(NSURLConnection *)connection didReceiveData:(NSData *)data
 {
     NSLog(@"didReceiveData : %@", data);
     [self.receivedData appendData:data];
  }

  (void)connection:(NSURLConnection *)connection didFailWithError:(NSError *)error
 {
      NSLog(@"didFailWithError");
 }

  (void)connectionDidFinishLoading:(NSURLConnection *)connection
 {
     NSString *resultString = [[NSString alloc] initWithData:self.receivedData encoding:NSUTF8StringEncoding];
     NSLog(@"result : %@", resultS tring);

      [self performSelectorOnMainThread:@selector(didSendMessage:) withObject:resultString waitUntilDone:NO];
  }


I get the following log.

    2012-04-11 00:13:59.177 M[7682:707] didReceiveResponse

    2012-04-11 00:13:59.179 M[7682:707] result : 

    No header response is sent back.

该请求需要以下内容：

  • 地点（号码）
  • 点（数）
  • 数（数）
  • 消息（字符串）
  • 已发送（日期时间：yyyy-MM-dd HH:mm:ss）

这是一个没有安全部分以减少长度的 PHP 代码。

  1. 处理从 case = post 开始的所有内容的调用（get 用于检索消息）

    $request = RestUtils::processRequest();

switch ($request->getMethod()){
    case 'get':
    case 'post':
        $db = get_db();
        $response = array();
        $response["message"] = array();     
        $data = $request->getRequestVars();
        $location = htmlspecialchars($data["location"]);
        $point = htmlspecialchars($data["point"]);
        $area = get_area($point, $location, $db);
        $employee = get_employee($request, $area, $db);
        $message_id = add_message($response["message"], $request, $area, $db);      
        if($employee == false){
            $response["error"] = "mo.";
            $response["pushed"] = 0;
            RestUtils::sendResponse(410, json_encode($response), 'application/json');
            exit;
        }
        $response["pushed"] = array();
        $response["error"] = array();
        $number = htmlspecialchars($data['number']);
        switch($employee["phone_Type"]){
            case 1:
                if(is_blocked($number)){
                    $response["error"] = "You're Number is Blocked";
                    $response["pushed"] = 0;
                    RestUtils::sendResponse(503, json_encode($response), 'application/json');
                    exit;
                }
                if(push_android($employee["device_ID"], $message_id, $point, $location) == false){
                    $response["error"] = "Service Temporally Unavailable";
                    $response["pushed"] = 0;
                    RestUtils::sendResponse(400, json_encode($response), 'application/json');
                    exit;
                }
                $response["pushed"] = 1;
                break;
            case 2:
                if(is_blocked($number)){
                    $response["error"] = "You're Number is Blocked";
                    $response["pushed"] = 0;
                    RestUtils::sendResponse(503, json_encode($response), 'application/json');
                    exit;
                }
                push_iOS($employee["device_ID"], $message_id, $point, $location);
                $response["pushed"] = 1;
                break;
            default:
                $response["pushed"] = 0;
                $response["error"] = 'Unsupported Phone Type';
                RestUtils::sendResponse(406, json_encode($response), 'application/json');
        }
        $db->close();
        RestUtils::sendResponse(200, json_encode($response), 'application/json');
        break;
}

  2. 这是支持功能：

    function build_post_query($area, $point, $location, $message, $number, $sent){
    return "INSERT INTO messages (message_ID, area_ID, point_ID, location_ID, message_Sent, message_Text, message_Number, message_Viewed) VALUES (NULL, ".$area.", ".$point.", ".$location.", '".$sent."', '".$message."', '".$number."', 0)";
}

function add_message(&$response, $request, $area, $db){
    $data = $request->getRequestVars();
    $point = htmlspecialchars($data["point"]);
    $location = htmlspecialchars($data["location"]);
    $area = get_area($point, $location, $db);
    $sent = htmlspecialchars($data["sent"]);// 'yyyy-mm-dd HH:mm:ss' format from users phone
    $message = htmlspecialchars($data["message"]);
    $number = htmlspecialchars($data["number"]);
    $query = build_post_query($area, $point, $location, $message, $number, $sent);
    $result = $db->query($query);
    $response["message"] = array('saved'=>$db->affected_rows);
    $message_id = $db->insert_id;

    return $message_id;
}

function get_area($p, $loc, $db){
    $query = "SELECT area_ID FROM points WHERE point_ID = ".$p." AND location_ID = ".$loc;
    $result = $db->query($query);
    $result = $result->fetch_assoc();

    return $result["area_ID"];
}

function get_employee($request, $area, $db){
    $data = $request->getRequestVars();
    $point = htmlspecialchars($data["point"]);
    $location = htmlspecialchars($data["location"]);
    $query = "SELECT device_ID, phone_Type, employee_Phone FROM active_employees WHERE area_ID = ".$area." AND location_ID = ".$location;
    $result = $db->query($query);
    if($result->num_rows > 1){
        $employees = array();
        while($row = $result->fetch_assoc()){
            array_push($employees, $row);
        }
        return $employees;
    }
    if($result->num_rows == 1){
        return $result->fetch_assoc();
    }
    return false;
}
4

2 回答 2

0

是否有可能记录应该由 php 处理的请求？信息太少，无法在这里给出有意义的答案。

于 2012-04-10T14:58:36.153 回答
0

我认为你得到的是一堆 php 代码，因为你发送的任何数据都没有插入数据库。我认为可能有两个原因。

发送数据有问题或接收数据有问题

使用 post 方法，如下面的代码

NSString *string=@"Your url";

NSURL *url = [NSURL URLWithString:string];

NSMutableURLRequest *request = [[NSMutableURLRequest alloc]initWithURL:url];
[request setHTTPMethod:@"POST"];

NSString *mpfBoundry = [NSString stringWithString:@"---------------------------"];
NSString *contentType = [NSString stringWithFormat:@"application/x-www-form-urlencoded; boundary=%@", mpfBoundry];
[request addValue:contentType forHTTPHeaderField: @"Content-Type"]; 

    NSString* body =[NSString stringWithFormat:@"column1=%@&column2=%@&column3=%@", data1,data2,data3];

[request setHTTPBody:[body dataUsingEncoding:NSUTF8StringEncoding]];

NSURLConnection *connection= [[NSURLConnection alloc]initWithRequest:request delegate:self];

[connection start];
于 2012-04-10T17:44:55.680 回答