7

我可以使用来自各种在线资源的代码片段对 IPv4 进行此操作。我想知道是否有办法用 IPv6 做到这一点。

基本上我只需要一个可以输入 IPv6 地址和前缀(例如:address/68)的表格,它会计算网络地址、第一个可用地址、最后一个可用地址和广播地址。然后只是打印到屏幕上。不打算将其存储在数据库或任何东西中。

我该怎么做呢?

提前感谢大家!

4

4 回答 4

7

首先:IPv6 没有网络和广播地址。您可以在前缀中使用所有地址。第二:在 LAN 上,前缀长度总是(嗯,99.x% 的时间)a /64。路由 /68 会破坏 IPv6 功能,例如无状态自动配置。

下面是 IPv6 前缀计算器的详细实现:

<?php

/*
 * This is definitely not the fastest way to do it!
 */

// An example prefix
$prefix = '2001:db8:abc:1400::/54';

// Split in address and prefix length
list($firstaddrstr, $prefixlen) = explode('/', $prefix);

// Parse the address into a binary string
$firstaddrbin = inet_pton($firstaddrstr);

// Convert the binary string to a string with hexadecimal characters
# unpack() can be replaced with bin2hex()
# unpack() is used for symmetry with pack() below
$firstaddrhex = reset(unpack('H*', $firstaddrbin));

// Overwriting first address string to make sure notation is optimal
$firstaddrstr = inet_ntop($firstaddrbin);

// Calculate the number of 'flexible' bits
$flexbits = 128 - $prefixlen;

// Build the hexadecimal string of the last address
$lastaddrhex = $firstaddrhex;

// We start at the end of the string (which is always 32 characters long)
$pos = 31;
while ($flexbits > 0) {
  // Get the character at this position
  $orig = substr($lastaddrhex, $pos, 1);

  // Convert it to an integer
  $origval = hexdec($orig);

  // OR it with (2^flexbits)-1, with flexbits limited to 4 at a time
  $newval = $origval | (pow(2, min(4, $flexbits)) - 1);

  // Convert it back to a hexadecimal character
  $new = dechex($newval);

  // And put that character back in the string
  $lastaddrhex = substr_replace($lastaddrhex, $new, $pos, 1);

  // We processed one nibble, move to previous position
  $flexbits -= 4;
  $pos -= 1;
}

// Convert the hexadecimal string to a binary string
# Using pack() here
# Newer PHP version can use hex2bin()
$lastaddrbin = pack('H*', $lastaddrhex);

// And create an IPv6 address from the binary string
$lastaddrstr = inet_ntop($lastaddrbin);

// Report to user
echo "Prefix: $prefix\n";
echo "First: $firstaddrstr\n";
echo "Last: $lastaddrstr\n";

?>

它应该输出:

Prefix: 2001:db8:abc:1400::/54
First: 2001:db8:abc:1400::
Last: 2001:db8:abc:17ff:ffff:ffff:ffff:ffff
于 2012-04-10T09:44:18.663 回答
3

对于那些偶然发现这个问题的人,您可以使用GitHub 上dtr_pton的anddtr_ntop函数和dTRIP类更有效地做到这一点。

我们还注意到 PHP 中缺少 IPv6 的重点和工具,因此将这篇文章放在一起,http://www.highonphp.com/5-tips-for-working-with-ipv6-in-php,可能是对他人的帮助。

函数源

这将和 IP 转换为二进制表示:

/**
 * dtr_pton
 *
 * Converts a printable IP into an unpacked binary string
 *
 * @author Mike Mackintosh - mike@bakeryphp.com
 * @param string $ip
 * @return string $bin
 */
function dtr_pton( $ip ){

    if(filter_var($ip, FILTER_VALIDATE_IP, FILTER_FLAG_IPV4)){
        return current( unpack( "A4", inet_pton( $ip ) ) );
    }
    elseif(filter_var($ip, FILTER_VALIDATE_IP, FILTER_FLAG_IPV6)){
        return current( unpack( "A16", inet_pton( $ip ) ) );
    }

    throw new \Exception("Please supply a valid IPv4 or IPv6 address");

    return false;
}

这会将二进制表示转换为可打印的 IP:

/**
 * dtr_ntop
 *
 * Converts an unpacked binary string into a printable IP
 *
 * @author Mike Mackintosh - mike@bakeryphp.com
 * @param string $str
 * @return string $ip
 */
function dtr_ntop( $str ){
    if( strlen( $str ) == 16 OR strlen( $str ) == 4 ){
        return inet_ntop( pack( "A".strlen( $str ) , $str ) );
    }

    throw new \Exception( "Please provide a 4 or 16 byte string" );

    return false;
}

例子

使用该dtr_pton功能,您可以:

$ip = dtr_pton("fe80:1:2:3:a:bad:1dea:dad");
$mask = dtr_pton("ffff:ffff:ffff:ffff:ffff:fff0::");

获取您的网络和广播:

var_dump( dtr_ntop( $ip & $mask ) );
var_dump( dtr_ntop( $ip | ~ $mask ) );

你的输出将是:

string(18) "fe80:1:2:3:a:ba0::"
string(26) "fe80:1:2:3:a:baf:ffff:ffff"
于 2013-04-02T19:46:08.037 回答
1

好吧,为了后代,我在code这里添加我的。还要感谢你们帮助我确定这一点,因为我需要它来编写 ipv6/ip2country 脚本

它受到@ mikemacintosh和@ Sander Steffann在这里发布的代码的轻微启发,略有改进(异想天开的想法)并返回一个很好的对象,包含您需要/不需要的所有数据:

/**
* This:
* <code>
* Ipv6_Prefix2Range('2001:43f8:10::/48');
* </code>
* returns this:
* <code>
* object(stdClass)#2 (4) {
*   ["Prefix"]=>
*   string(17) "2001:43f8:10::/48"
*   ["FirstHex"]=>
*   string(32) "200143f8001000000000000000000000"
*   ["LastHex"]=>
*   string(32) "200143f80010ffffffffffffffffffff"
*   ["MaskHex"]=>
*   string(32) "ffffffffffff00000000000000000000"
*   // Optional bin equivalents available
* }
* </code>
* 
* Tested against:
* @link https://www.ultratools.com/tools/ipv6CIDRToRange
* 
* @param string $a_Prefix
* @param bool $a_WantBins
* @return object
*/
function Ipv6_Prefix2Range($a_Prefix, $a_WantBins = false){
    // Validate input superficially with a RegExp and split accordingly
    if(!preg_match('~^([0-9a-f:]+)[[:punct:]]([0-9]+)$~i', trim($a_Prefix), $v_Slices)){
        return false;
    }
    // Make sure we have a valid ipv6 address
    if(!filter_var($v_FirstAddress = $v_Slices[1], FILTER_VALIDATE_IP, FILTER_FLAG_IPV6)){
        return false;
    }
    // The /## end of the range
    $v_PrefixLength = intval($v_Slices[2]);
    if($v_PrefixLength > 128){
        return false; // kind'a stupid :)
    }
    $v_SuffixLength = 128 - $v_PrefixLength;

    // Convert the binary string to a hexadecimal string
    $v_FirstAddressBin = inet_pton($v_FirstAddress);
    $v_FirstAddressHex = bin2hex($v_FirstAddressBin);

    // Build the hexadecimal string of the network mask
    // (if the manually formed binary is too large, base_convert() chokes on it... so we split it up)
    $v_NetworkMaskHex = str_repeat('1', $v_PrefixLength) . str_repeat('0', $v_SuffixLength);
    $v_NetworkMaskHex_parts = str_split($v_NetworkMaskHex, 8);
    foreach($v_NetworkMaskHex_parts as &$v_NetworkMaskHex_part){
        $v_NetworkMaskHex_part = base_convert($v_NetworkMaskHex_part, 2, 16);
        $v_NetworkMaskHex_part = str_pad($v_NetworkMaskHex_part, 2, '0', STR_PAD_LEFT);
    }
    $v_NetworkMaskHex = implode(null, $v_NetworkMaskHex_parts);
    unset($v_NetworkMaskHex_part, $v_NetworkMaskHex_parts);
    $v_NetworkMaskBin = inet_pton(implode(':', str_split($v_NetworkMaskHex, 4)));

    // We have the network mask so we also apply it to First Address
    $v_FirstAddressBin &= $v_NetworkMaskBin;
    $v_FirstAddressHex = bin2hex($v_FirstAddressBin);

    // Convert the last address in hexadecimal
    $v_LastAddressBin = $v_FirstAddressBin | ~$v_NetworkMaskBin;
    $v_LastAddressHex =  bin2hex($v_LastAddressBin);

    // Return a neat object with information
    $v_Return = array(
        'Prefix'    => "{$v_FirstAddress}/{$v_PrefixLength}",
        'FirstHex'  => $v_FirstAddressHex,
        'LastHex'   => $v_LastAddressHex,
        'MaskHex'   => $v_NetworkMaskHex,
    );
    // Bins are optional...
    if($a_WantBins){
        $v_Return = array_merge($v_Return, array(
            'FirstBin'  => $v_FirstAddressBin,
            'LastBin'   => $v_LastAddressBin,
            'MaskBin'   => $v_NetworkMaskBin,
        ));
    }
    return (object)$v_Return;
}

我喜欢函数和类,不喜欢实现可重用功能的不可重用代码。

PS如果您发现它有问题,请回复我。我远非 IPv6 专家。

于 2013-04-07T18:26:52.923 回答
1

这是对接受的答案的修复,它错误地假设“第一个地址”应该与输入的字符串相同。相反,它需要通过AND运算符对其掩码进行修改。

为了演示该问题,请考虑以下示例输入:2001:db8:abc:1403::/54

预期结果:

First: 2001:db8:abc:1400::

实际结果:

First: 2001:db8:abc:1403::

计算给定 4 位序列的掩码的相关数学是:

// Calculate the subnet mask. min() prevents the comparison from being negative
$mask = 0xf << (min(4, $flexbits));

// AND the original against its mask
$newval = $origval & $mask;

完整代码

<?php

/*
 * This is definitely not the fastest way to do it!
 */

// An example prefix
$prefix = '2001:db8:abc:1403::/54';

// Split in address and prefix length
list($addr_given_str, $prefixlen) = explode('/', $prefix);

// Parse the address into a binary string
$addr_given_bin = inet_pton($addr_given_str);

// Convert the binary string to a string with hexadecimal characters
$addr_given_hex = bin2hex($addr_given_bin);

// Overwriting first address string to make sure notation is optimal
$addr_given_str = inet_ntop($addr_given_bin);

// Calculate the number of 'flexible' bits
$flexbits = 128 - $prefixlen;

// Build the hexadecimal strings of the first and last addresses
$addr_hex_first = $addr_given_hex;
$addr_hex_last = $addr_given_hex;

// We start at the end of the string (which is always 32 characters long)
$pos = 31;
while ($flexbits > 0) {
    // Get the characters at this position
    $orig_first = substr($addr_hex_first, $pos, 1);
    $orig_last = substr($addr_hex_last, $pos, 1);

    // Convert them to an integer
    $origval_first = hexdec($orig_first);
    $origval_last = hexdec($orig_last);

    // First address: calculate the subnet mask. min() prevents the comparison from being negative
    $mask = 0xf << (min(4, $flexbits));

    // AND the original against its mask
    $new_val_first = $origval_first & $mask;

    // Last address: OR it with (2^flexbits)-1, with flexbits limited to 4 at a time
    $new_val_last = $origval_last | (pow(2, min(4, $flexbits)) - 1);

    // Convert them back to hexadecimal characters
    $new_first = dechex($new_val_first);
    $new_last = dechex($new_val_last);

    // And put those character back in their strings
    $addr_hex_first = substr_replace($addr_hex_first, $new_first, $pos, 1);
    $addr_hex_last = substr_replace($addr_hex_last, $new_last, $pos, 1);

    // We processed one nibble, move to previous position
    $flexbits -= 4;
    $pos -= 1;
}

// Convert the hexadecimal strings to a binary string
$addr_bin_first = hex2bin($addr_hex_first);
$addr_bin_last = hex2bin($addr_hex_last);

// And create an IPv6 address from the binary string
$addr_str_first = inet_ntop($addr_bin_first);
$addr_str_last = inet_ntop($addr_bin_last);

// Report to user
echo "Prefix: $prefix\n";
echo "First: $addr_str_first\n";
echo "Last: $addr_str_last\n";

输出:

Prefix: 2001:db8:abc:1403::/54
First: 2001:db8:abc:1400::
Last: 2001:db8:abc:17ff:ffff:ffff:ffff:ffff

于 2020-05-19T04:03:46.820 回答