15

设想：

  • 用户点击一个按钮，要求对地址簿进行某种修改。
  • 调用一个方法来启动此修改并显示一个警报视图。

  • 为了显示警报视图并保持 UI 响应，我使用了 dispatch_queue：

    dispatch_async(dispatch_get_global_queue(DISPATCH_QUEUE_PRIORITY_DEFAULT, 0), ^{
                 dispatch_sync(dispatch_get_main_queue(), ^{
                   // Show the alert view
                 });
               });

  • 使用以下命令启动地址簿修改过程：

    dispatch_async(modifyingAddressBookQueue, ^{});

现在，我想为用户提供随时取消进程的能力（当然是在保存地址簿之前）。因此，当他点击警报表中的取消按钮时，我想访问调度块，设置一些特定的 BOOL 来停止进程并恢复通讯簿。

问题是，你不能这样做！您无法访问该块并更改其中的任何变量，因为所有变量仅复制一次。执行时块内的任何变量更改都不会被块看到。

总结一下：如何使用 UI 事件停止正在进行的操作？

更新：

该过程的代码：

- (void) startFixingModification {

    _fixContacts = YES;
    __block BOOL cancelled = NO;

    dispatch_queue_t modifyingAddressBookQueue;
    modifyingAddressBookQueue = dispatch_queue_create(sModifyingAddressBookQueueIdentifier,
                                                      NULL);

    dispatch_async(modifyingAddressBookQueue, ^{

        for (NSMutableDictionary *contactDictionary in _contactArray) {

            if (!cancelled) {
                break;
            }

            i = i + 1;

            BOOL didFixContact = [self fixNumberInContactDictionary:contactDictionary];
            if (!didFixContact) {
                _fixedNumbers = _fixedNumbers - 1;
            }

            dispatch_async(dispatch_get_global_queue(DISPATCH_QUEUE_PRIORITY_DEFAULT, 0), ^{
                dispatch_sync(dispatch_get_main_queue(), ^{
                    [self setAlertViewProgress:i];
                });

            });
        }
    });

    cancelledPtr = &cancelled;

}

alertview（我自己的库）委托的代码

- (void) alertViewProgressCancel:(ASAlertViewProgress *)alertView { // This is a private lib.


    if (cancelledPtr)
    {
        NSLog(@"stopping");

        *cancelledPtr = YES;
    }

}

在界面中，我声明

BOOL*   cancelledPtr;

更新 2：

真的越来越令人沮丧了！对于以下代码

for (NSMutableDictionary *contactDictionary in _contactArray) {

            NSLog(@"%d", _cancelModification);
            if (_cancelModification) {
                break;
            }
}

如果 _cancelModification 设置为 YES，则 for 循环被破坏，这没关系。一旦我注释掉 NSLog 行，当它变为 YES 时，_cancelModification 就会被忽略！

4

3 回答 3

21

如果你声明你的BOOLusing __block，那么它可以在块执行之外进行更改，并且块将看到新值。有关更多详细信息，请参阅文档。

一个例子：

@interface SNViewController ()
{
    BOOL*   cancelledPtr;
}

@end

@implementation SNViewController

- (IBAction)start:(id)sender
{
    __block BOOL cancelled = NO;

    dispatch_async(dispatch_get_global_queue(DISPATCH_QUEUE_PRIORITY_DEFAULT, 0), ^{
        while (!cancelled) {
            NSLog(@"running");
            sleep(1);
        }        
        NSLog(@"stopped");
    });

    cancelledPtr = &cancelled;
}

- (IBAction)stop:(id)sender
{
    if (cancelledPtr)
    {
        NSLog(@"stopping");

        *cancelledPtr = YES;
    }
}

@end

或者，在您的类中使用 ivar 来存储 BOOL。该块将隐式复制self并通过它访问 ivar。不需要__block。

@interface SNViewController ()
{
    BOOL   cancelled;
}

@end

@implementation SNViewController

- (IBAction)start:(id)sender
{
    dispatch_async(dispatch_get_global_queue(DISPATCH_QUEUE_PRIORITY_DEFAULT, 0), ^{
        while (!cancelled) {
            NSLog(@"running");
            sleep(1);
        }        
        NSLog(@"stopped");
    });
}

- (IBAction)stop:(id)sender
{
    NSLog(@"stopping");
    cancelled = YES;
}

@end
于 2012-04-08T22:05:12.563 回答
7

方法一

创建一个返回“可取消”块的自定义 dispatch_async 方法。

// The dispatch_cancel_block_t takes as parameter the "cancel" directive to suspend the block execution or not whenever the block to execute is dispatched. 
// The return value is a boolean indicating if the block has already been executed or not.
typedef BOOL (^dispatch_cancel_block_t)(BOOL cancelBlock);

dispatch_cancel_block_t dispatch_async_with_cancel_block(dispatch_queue_t queue, void (^block)())
{
    __block BOOL execute = YES;
    __block BOOL executed = NO;

    dispatch_cancel_block_t cancelBlock = ^BOOL (BOOL cancelled) {
        execute = !cancelled;
        return executed == NO;
    };

    dispatch_async(queue, ^{
        if (execute)
            block();
        executed = YES;
    });

    return cancelBlock;
}

- (void)testCancelableBlock
{
    dispatch_cancel_block_t cancelBlock = dispatch_async_with_cancel_block(dispatch_get_main_queue(), ^{
        NSLog(@"Block 1 executed");
    });

    // Canceling the block execution
    BOOL success1 = cancelBlock(YES);
    NSLog(@"Block is cancelled successfully: %@", success1?@"YES":@"NO");

    // Resuming the block execution
    // BOOL success2 = cancelBlock(NO);
    // NSLog(@"Block is resumed successfully: %@", success2?@"YES":@"NO");
}

方法二

如果条件得到验证，定义一个用于异步执行块的宏：

#define dispatch_async_if(queue,condition,block) \
dispatch_async(queue, ^{\
    if (condition == YES)\
        block();\
});

- (void)testConditionBlock
{
    // Creating condition variable
    __block BOOL condition = YES;

    dispatch_async_if(dispatch_get_main_queue(), condition, ^{
        NSLog(@"Block 2 executed");
    });

    // Canceling the block execution
    condition = NO;

    // Also, we could use a method to test the condition status
    dispatch_async_if(dispatch_get_main_queue(), ![self mustCancelBlockExecution], ^{
        NSLog(@"Block 3 executed");
    });
}
于 2014-11-05T18:00:08.047 回答
0

尝试将以下代码示例应用于您的情况：

__block UIView * tempView = [[UIView alloc] initWithFrame:CGRectMake(50, 100, 220, 30)];
[tempView setBackgroundColor:[UIColor grayColor]];
[self.view addSubview:tempView];
[tempView release];

__block BOOL cancel = NO;
//点击之后就会开始执行这个方法
dispatch_queue_t queue = dispatch_get_global_queue(DISPATCH_QUEUE_PRIORITY_DEFAULT, 0);
dispatch_async(queue, ^{
    int i = 0;
    while (i < 1000000000 && cancel == NO) {
        i++;
    }
    NSLog(@"Task end: i = %d", i);
    //这个不会执行，因为在之前，gcd task已经结束
    [tempView removeFromSuperview];
});

//1s 之后执行这个方法
double delayInSeconds = 1.0;
dispatch_time_t popTime = dispatch_time(DISPATCH_TIME_NOW, (int64_t)(delayInSeconds * NSEC_PER_SEC));
dispatch_after(popTime, dispatch_get_main_queue(), ^(void){
    NSLog(@"A GCD Task Start");
    cancel = YES;
    [tempView setBackgroundColor:[UIColor blackColor]];
});
于 2013-05-08T11:54:16.290 回答