5

我有一个包含一系列 (IP varchar(15), DateTime datetime2) 值的表。每行对应一个用户发出的 HTTP 请求。我想将会话编号分配给这些行。不同的 IP 地址有不同的会话号。如果最后一个请求早于 30min ，则应为相同的 IP 分配一个新的会话号。这是一个示例输出：

IP,      DateTime,         SessionNumber, RequestNumber
1.1.1.1, 2012-01-01 00:01, 1,             1
1.1.1.1, 2012-01-01 00:02, 1,             2
1.1.1.1, 2012-01-01 00:03, 1,             3
1.1.1.2, 2012-01-01 00:04, 2,             1 --different IP => new session number
1.1.1.2, 2012-01-01 00:05, 2,             2
1.1.1.2, 2012-01-01 00:40, 3,             1 --same IP, but last request 35min ago (> 30min)

第 1 列和第 2 列是输入，第 3 列和第 4 列是所需的输出。该表显示了两个用户。

由于底层表确实很大，如何有效地解决这个问题？我更喜欢对数据进行少量恒定的传递（一个或两个）。

4

2 回答 2

8

这里有几个尝试。

;WITH CTE1 AS
(
SELECT *,
IIF(DATEDIFF(MINUTE,
       LAG(DateTime) OVER (PARTITION BY IP ORDER BY DateTime),
       DateTime) < 30,0,1) AS SessionFlag
FROM Sessions
), CTE2 AS
(
SELECT *,
       SUM(SessionFlag) OVER (PARTITION BY IP 
                                  ORDER BY DateTime) AS IPSessionNumber
FROM CTE1
)
SELECT IP,
       DateTime,
       DENSE_RANK() OVER (ORDER BY IP, IPSessionNumber) AS SessionNumber,
       ROW_NUMBER() OVER (PARTITION BY IP, IPSessionNumber 
                              ORDER BY DateTime) AS RequestNumber
FROM CTE2

这有两个排序操作（IP, DateTime然后按IP, IPSessionNumber），但假设SessionNumber可以任意分配，只要根据 ip 地址/30 分钟规则为每个新会话分配不同的唯一会话号。

SessionNumber按时间顺序依次分配s。我用了以下。

;WITH CTE1 AS
(
SELECT *,
IIF(DATEDIFF(MINUTE,
       LAG(DateTime) OVER (PARTITION BY IP ORDER BY DateTime),
       DateTime) < 30,0,1) AS SessionFlag
FROM Sessions
), CTE2 AS(
SELECT *,
       SUM(SessionFlag) OVER (ORDER BY DateTime) AS GlobalSessionNo
FROM CTE1
), CTE3 AS(
SELECT *,
       MAX(CASE WHEN SessionFlag = 1 THEN GlobalSessionNo END) 
               OVER (PARTITION BY IP ORDER BY DateTime) AS SessionNumber
FROM CTE2)
SELECT IP,
       DateTime,
       SessionNumber,
       ROW_NUMBER() OVER (PARTITION BY SessionNumber 
                              ORDER BY DateTime) AS RequestNumber
FROM CTE3

但是，这会将排序操作的数量增加到 4。

于 2012-04-08T19:13:41.263 回答
2

这是一个使用表变量和 row_number 来创建可在递归 CTE 中使用的 ID 的版本。将性能与游标和一个查询（由 Martin 提供）版本进行比较可能是值得的。

CREATE TABLE #T
(
  IP varchar(15),
  DateTime datetime,
  ID int,
  primary key (IP, ID)
)

insert into #T(IP, DateTime, ID)
select IP, DateTime, row_number() over(partition by IP order by DateTime) 
from #sessionRequests

;with C as
(
  select IP,
         ID,
         DateTime,
         1 as Session
  from #T
  where ID = 1
  union all 
  select T.IP,
         T.ID,
         T.DateTime,
         C.Session + case when datediff(minute, C.DateTime, T.DateTime) >= 30 then 1 else 0 end
  from #T as T
    inner join C 
      on T.IP = C.IP and
         T.ID = C.ID + 1
)
SELECT IP,
       DateTime,
       dense_rank() over(order by IP, Session) as SessionNumber,
       row_number() over(partition by IP, Session order by DateTime) as RequestNumber
from C
order by IP, DateTime, SessionNumber, RequestNumber
option (maxrecursion 0)
于 2012-04-09T07:28:05.953 回答