c# - 如何以编程方式向 datagridview 添加新行

Question

如果添加行DataTable

DataRow row = datatable1.NewRow();
row["column2"]="column2";
row["column6"]="column6";
datatable1.Rows.Add(row);

怎么样DataGridView？？

Answer 1

你可以做：

DataGridViewRow row = (DataGridViewRow)yourDataGridView.Rows[0].Clone();
row.Cells[0].Value = "XYZ";
row.Cells[1].Value = 50.2;
yourDataGridView.Rows.Add(row);

或者：

DataGridViewRow row = (DataGridViewRow)yourDataGridView.Rows[0].Clone();
row.Cells["Column2"].Value = "XYZ";
row.Cells["Column6"].Value = 50.2;
yourDataGridView.Rows.Add(row);

另一种方式：

this.dataGridView1.Rows.Add("five", "six", "seven","eight");
this.dataGridView1.Rows.Insert(0, "one", "two", "three", "four");

来自：http: //msdn.microsoft.com/en-us/library/system.windows.forms.datagridview.rows.aspx

Answer 2

像这样：

var index = dgv.Rows.Add();
dgv.Rows[index].Cells["Column1"].Value = "Column1";
dgv.Rows[index].Cells["Column2"].Value = 5.6;
//....

Answer 3

假设您有一个未绑定到数据集的 datagridview，并且您希望以编程方式填充新行...

这是你如何做到的。

// Create a new row first as it will include the columns you've created at design-time.

int rowId = dataGridView1.Rows.Add();

// Grab the new row!
DataGridViewRow row = dataGridView1.Rows[rowId];

// Add the data
row.Cells["Column1"].Value = "Value1";
row.Cells["Column2"].Value = "Value2";

// And that's it! Quick and painless... :o)

Answer 4

像这样：

 dataGridView1.Columns[0].Name = "column2";
 dataGridView1.Columns[1].Name = "column6";

 string[] row1 = new string[] { "column2 value", "column6 value" };
 dataGridView1.Rows.Add(row1);

或者您需要使用属性单独设置值.Rows()，如下所示：

 dataGridView1.Rows[1].Cells[0].Value = "cell value";

Answer 5

使用Add()在 DGV 中添加没有行的新行会引发SelectionChanged事件，然后您才能插入任何数据（或在 Tag 属性中绑定对象）。

从RowTemplate创建一个克隆行更安全恕我直言：

//assuming that you created columns (via code or designer) in myDGV
DataGridViewRow row = (DataGridViewRow) myDGV.RowTemplate.Clone();
row.CreateCells(myDGV, "cell1", "cell2", "cell3");

myDGV.Rows.Add(row);

Answer 6

如果 dgrview 为空，这就是我添加行的方式：（myDataGridView 在我的示例中有两列）

DataGridViewRow row = new DataGridViewRow();
row.CreateCells(myDataGridView);

row.Cells[0].Value = "some value";
row.Cells[1].Value = "next columns value";

myDataGridView.Rows.Add(row);

根据文档：“CreateCells() 清除现有单元格并根据提供的 DataGridView 模板设置其模板”。

Answer 7

如果网格与 DataSet / 表绑定，则最好使用 BindingSource 之类的

var bindingSource = new BindingSource();
bindingSource.DataSource = dataTable;
grid.DataSource = bindingSource;

//Add data to dataTable and then call

bindingSource.ResetBindings(false)    

Answer 8

这是另一种方法

 private void dataGridView1_CellContentClick(object sender, DataGridViewCellEventArgs e)
    {
        dataGridView1.ColumnCount = 3;

        dataGridView1.Columns[0].Name = "Name";
        dataGridView1.Columns[1].Name = "Age";
        dataGridView1.Columns[2].Name = "City";

        dataGridView1.Rows.Add("kathir", "25", "salem");
        dataGridView1.Rows.Add("vino", "24", "attur");
        dataGridView1.Rows.Add("maruthi", "26", "dharmapuri");
        dataGridView1.Rows.Add("arun", "27", "chennai"); 
    }

Answer 9

如果您需要操作除单元格值字符串之外的任何内容（例如添加标签），请尝试以下操作：

DataGridViewRow newRow = (DataGridViewRow)mappingDataGridView.RowTemplate.Clone();
newRow.CreateCells(mappingDataGridView);

newRow.Cells[0].Value = mapping.Key;
newRow.Cells[1].Value = ((BusinessObject)mapping.Value).Name;
newRow.Cells[1].Tag = mapping.Value;

mappingDataGridView.Rows.Add(newRow);

Answer 10

如果您正在绑定列表

List<Student> student = new List<Student>();

dataGridView1.DataSource = student.ToList();
student .Add(new Student());

//Reset the Datasource
dataGridView1.DataSource = null;
dataGridView1.DataSource = student;

如果您正在绑定 DataTable

DataTable table = new DataTable();

 DataRow newRow = table.NewRow();

// Add the row to the rows collection.
table.Rows.Add(newRow);

Answer 11

yourDGV.Rows.Add(column1,column2...columnx); //add a row to a dataGridview
yourDGV.Rows[rowindex].Cells[Cell/Columnindex].value = yourvalue; //edit the value

您还可以创建一个新行，然后将其添加到 DataGridView 中，如下所示：

DataGridViewRow row = new DataGridViewRow();
row.Cells[Cell/Columnindex].Value = yourvalue;
yourDGV.Rows.Add(row);

Answer 12

如果有人想将 DataTable 添加为 gridview 的源，那么 -

DataTable dt = new DataTable();
dt.Columns.Add(new DataColumn("column1"));
dt.Columns.Add(new DataColumn("column2"));

DataRow dr = dt.NewRow();
dr[0] = "column1 Value";
dr[1] = "column2 Value";

dt.Rows.Add(dr);

dataGridView1.DataSource = dt;

Answer 13

//Add a list of BBDD
var item = myEntities.getList().ToList();
//Insert a new object of type in a position of the list       
item.Insert(0,(new Model.getList_Result { id = 0, name = "Coca Cola" }));

//List assigned to DataGridView
dgList.DataSource = item; 

Answer 14

从 dataGridView 复制行并在同一 dataGridView 中添加新行的示例：

DataTable Dt = new DataTable();
Dt.Columns.Add("Column1");
Dt.Columns.Add("Column2");

DataRow dr = Dt.NewRow();
DataGridViewRow dgvR = (DataGridViewRow)dataGridView1.CurrentRow;
dr[0] = dgvR.Cells[0].Value; 
dr[1] = dgvR.Cells[1].Value;              

Dt.Rows.Add(dR);
dataGridView1.DataSource = Dt;

Answer 15

//header
dataGridView1.RowCount = 50;
dataGridView1.Rows[0].HeaderCell.Value = "Product_ID0";


//add row by cell 
 dataGridView1.Rows[1].Cells[0].Value = "cell value";

Answer 16

考虑一个 Windows 应用程序并使用按钮单击事件将这段代码放入其中。

dataGridView1.Rows
                .Add(new object[] { textBox1.Text, textBox2.Text, textBox3.Text });

Answer 17

如果您已经定义了 a DataSource，您可以获取DataGridView´sDataSource并将其转换为Datatable.

然后添加一个新的DataRow并设置字段值。

将新行添加到DataTable并接受更改。

在 C# 中它会是这样的..

DataTable dataTable = (DataTable)dataGridView.DataSource;
DataRow drToAdd = dataTable.NewRow();

drToAdd["Field1"] = "Value1";
drToAdd["Field2"] = "Value2";

dataTable.Rows.Add(drToAdd);
dataTable.AcceptChanges();

Answer 18

当 DataGrid 绑定到表时，我发现这不止一次有用。

        DataTable dt = (DataTable)dgvData.DataSource;
        DataRow row = dt.NewRow();
        foreach (var something in something)
        {
           row["ColumnName"] = something ;               
        }
        dt.Rows.Add(row);
        dgvData.DataSource = dt;

Answer 19

string[] splited = t.Split('>');
int index = dgv_customers.Rows.Add(new DataGridViewRow());
dgv_customers.Rows[index].Cells["cust_id"].Value=splited.WhichIsType("id;");

但请注意，WhichIsType是我创建的扩展方法。