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我正在开发一个应用程序。我需要在另一个 UIImageView 中显示 9 个 UIImageViews。如果我们单击任何图像，然后识别所选 UIImageView 并更改所选 UIImageView 的图像。下一次也需要做同样的事情，但我们需要用新更改的图像显示以前选择的图像。为此，我编写了类似的代码

for (int h=0; h<8; h++) 
      {
          int x=[[questions.marker_left objectAtIndex:h] intValue];
          int y=[[questions.marker_top objectAtIndex:h] intValue];
          img3=[[UIImageView alloc]initWithFrame:CGRectMake(x,y, 30, 30)];
          img3.userInteractionEnabled=YES;
          img1.userInteractionEnabled=YES;
          img3.tag=h;
          //img2.backgroundColor=[UIColor greenColor];
          img3.image=[UIImage imageNamed:@"PINpurple.png"];
          tap5=[[UITapGestureRecognizer alloc]initWithTarget:self action:@selector(calculate:)];
          tap5.delegate=self;
          [img3 addGestureRecognizer:tap5];
          [img1 addSubview:img3];

      }

  -(void)calculate:(UITapGestureRecognizer*)recognizer
   {
      NSInteger i=(recognizer).view.tag;
     NSString *str=[questions.result objectAtIndex:i];
      NSLog(@"%@",str);
     if([str isEqualToString:@"true"])
        {
          img3.image=[UIImage imageNamed:@"PINgreen.png"];
        }
     else
        {
          img3.image=[UIImage imageNamed:@"PINred.png"];
          }
   }

选择的图像将被更改，但在选择下一个 UIImageView 后，以前的 UIImageView 会得到旧图像。所以请帮助我，如何做到这一点？

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1 回答 1

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    //Edit In calculate function
    -(void)calculate:(UITapGestureRecognizer*)recognizer
    {
      NSInteger i=(recognizer).view.tag;

      //Detect selected UIImageView
      UIImageView *selectedImageView=(UIImageView*)recognizer.view;

      NSString *str=[questions.result objectAtIndex:i];

      NSLog(@"%@",str);

     if([str isEqualToString:@"true"])
        {
          selectedImageView.image=[UIImage imageNamed:@"PINgreen.png"];
        }
     else
        {
          selectedImageView.image=[UIImage imageNamed:@"PINred.png"];
        }
    }
于 2012-04-05T10:09:42.350 回答