1

在我的应用程序中,我使用这个线程来旋转时钟上的秒针。但问题是当我关闭活动时,线程仍在运行。我想停止线程,这样它就不会影响设备的 Bettry。

以下是我正在旋转时钟秒针的活动代码:

 public class ClockActivity extends Activity implements OnClickListener{
    private Button chimeBtn;
    private ImageView img;
    private Thread myThread = null;

    @Override
    public void onCreate(Bundle savedInstanceState){
        super.onCreate(savedInstanceState);
        setContentView(R.layout.clock_layout);


        Runnable runnable = new CountDownRunner();
        myThread = new Thread(runnable);
        myThread.start();

        chimeBtn = (Button) findViewById(R.id.chimeBtn);
        chimeBtn.setOnClickListener(this);
    }
    @Override
    public void onClick(View v) {
        switch(v.getId()){
            case R.id.chimeBtn:
                playSound(R.raw.one_bell);
                break;
        }
    }
    public void playSound(int resources){

         MediaPlayer mp = MediaPlayer.create(getApplicationContext(), resources);
            mp.start();


    }

    private void doPlay(){
        new Thread(new Runnable() {

            @Override
            public void run() {
                // TODO Auto-generated method stub

                Log.v("log_tag", "this is seocond thread");

            }
        }).start();
    }
    public void doRotate() {

        runOnUiThread(new Runnable() {
            public void run() {
                try {

                    Date dt = new Date();
                    int hours = dt.getHours();
                    int minutes = dt.getMinutes();
                    int seconds = dt.getSeconds();
                    String curTime = hours + ":" + minutes + "::" + seconds;
                    Log.v("log_tag", "Log is here Time is now" + curTime);
                    img = (ImageView) findViewById(R.id.imgsecond);
                    RotateAnimation rotateAnimation = new RotateAnimation((seconds - 1) * 6, seconds * 6,
                            Animation.RELATIVE_TO_SELF, 0.5f,Animation.RELATIVE_TO_SELF, 0.5f);

                    rotateAnimation.setInterpolator(new LinearInterpolator());
                    rotateAnimation.setFillAfter(true);

                    img.startAnimation(rotateAnimation);
                } catch (Exception e) {
                    Log.e("log_tag", "Error msg is " + e.toString());

                }
            }
        });
    }

    @Override
    public boolean onKeyDown(int keyCode, KeyEvent event) { 

        if (keyCode == KeyEvent.KEYCODE_BACK) {       
            System.out.println("Back Key Press");
            if (myThread != null) {

                   myThread.interrupt(); //says that the myThread should stop 
                   try{ 
                           myThread.join(); //make this myThread wait for the other myThread to  finish before returning
                           myThread = new Thread();
                           myThread = null;
                   }catch(InterruptedException ie){ 
                           //handle the case if the thread.join is interrupt 
                           //don't know if this will ever happen, if it can... throw a runtime exception?, or reinterrupt? 
                           Thread.currentThread().interrupt(); 
                           //   reinterrupt because thrown exception cleared interrupt and hope it's handled elsewhere 
                   } 

            }
            System.out.println("Back Key Press");
            return true;       
        }       
        return super.onKeyDown(keyCode, event);     
    } 

    @Override
    public void onDestroy(){

        System.out.println("OnDestroy");

        super.onDestroy();

    }

    class CountDownRunner implements Runnable {
        // @Override
        public void run() {
            while (!Thread.currentThread().isInterrupted()) {
                try {
                    // Log.v("log_tag", "Roate is going");
                    doRotate();
                    Thread.sleep(1000);
                    //doPlay();
                    } catch (InterruptedException e) 
                    {
                    // Thread.currentThread().interrupt();
                } catch (Exception e) {
                    Log.e("log_tag", "Error is " + e.toString());
                }
            }
        }
    }
}

提前致谢。

4

3 回答 3

5

在您的活动中尝试此代码 -

@Override
protected void onDestroy() {
    android.os.Process.killProcess(android.os.Process.myPid());
}

当您退出应用程序时,您的应用程序进程实际上并没有被破坏。如果您销毁您的进程,所有子进程(您的所有子线程)都将被销毁。

于 2012-04-05T10:05:31.753 回答
4

好的,这意味着您要创建一个将在后台运行的服务。一件事是服务是一种类型的线程,如果它将在后台运行会耗尽您的设备电池电量。所以,如果你杀死你的进程,那么线程和你的服务都会被破坏。所以,停止你的线程 -

boolean running = true;

public void run() {
   while(running) {
       // your working code...
   }
}

@Override
protected void onDestroy() {
    running = false;
}

当您退出应用程序时,线程将停止。另一个将继续运行,那就是您的服务。不要试图强行停止你的线程,或者暂停。它已被弃用,如果您的线程的 while 循环中断,那么它将根据 JVM 规则自动销毁您的线程。希望它会帮助你。玩得开心...

于 2012-04-06T05:23:15.540 回答
3

不要myThread.join()在 UI 线程上,因为它会阻塞,直到线程完成并且您的应用程序可能会 ANR。还会Thread.currentThread().interrupt();尝试中断非常糟糕的 UI 线程。

您可以放入MyThread.interrupt(),onDestroyonPause( onStop+ 在相应的启动回调中重新创建线程)

于 2012-04-05T09:59:39.093 回答