0

我有这样的查询：

SELECT EXTRACT(MONTH FROM d.mydate) AS synmonth, SUM(apcp) AS apcptot
FROM t_synop_data2 d
WHERE d.mydate
BETWEEN '2011-01-01' AND '2011-12-31' 
AND d.idx_synop = '06712'
GROUP BY synmonth

此查询添加一个月内的所有降雨（apcp），如下所示：

1   32.8  => from 2011.01.01 to 2011.01.31
2   27.2 => from 2011.02.01 to 2011.02.28
3   21.0
4   21.8
5   88.5
6   131.4
7   118.6
8   57.1
9   80.9
10  84.6
11  1.1
12  143.5 => from 2011.12.01 to 2011.12.31

这就是我想要的，但有一点不同。

这个区别是我必须从当月的第 2 天到下个月的第 1 天添加 apcp，然后返回类似上面的结果。

1   132.8 => from 2011.01.02 to 2011.02.01
2   27.2  => from 2011.02.02 to 2011.03.01
3   21.0
4   21.8
5   88.5
6   131.4
7   118.6
8   57.1
9   80.9
10  84.6
11  1.1
12  143.5 => from 2011.12.02 to 2012.01.01

我用 add_date()、extract() 或 date_format() 尝试了一些东西，但没有结果。

谢谢你的回答文斯

4

2 回答 2

1

这是查询：

SELECT EXTRACT(MONTH FROM ADDDATE(d.mydate,-1) ) AS synmonth
, SUM(apcp) AS apcptot
FROM t_synop_data2 AS d
WHERE ADDDATE(d.mydate,-1) BETWEEN '2011-01-01' AND '2012-12-31'
AND d.idx_synop = '06712'
GROUP BY synmonth

您可以通过添加两列来检查结果，如下所示：

SELECT EXTRACT(MONTH FROM ADDDATE(d.mydate,-1) ) AS synmonth
, SUM(apcp) AS apcptot
, MIN(d.mydate) AS date_min
, MAX(d.mydate) AS date_max
FROM t_synop_data2 AS d
WHERE ADDDATE(d.mydate,-1) BETWEEN '2011-01-01' AND '2012-12-31'
AND d.idx_synop = '06712'
GROUP BY synmonth
于 2012-04-03T20:59:12.563 回答
0

你可以分组EXTRACT(MONTH FROM d.mydate - INTERVAL 1 DAY) 

SELECT EXTRACT(MONTH FROM d.mydate) AS synmonth, SUM(apcp) AS apcptot
FROM t_synop_data2 d
WHERE d.mydate
BETWEEN '2011-01-01' AND '2011-12-31' 
AND d.idx_synop = '06712'
GROUP BY EXTRACT(MONTH FROM d.mydate - INTERVAL 1 DAY)
于 2012-04-03T20:56:02.563 回答