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我正在尝试编写一个 MySQL 查询，它为我提供组织名称、其邮政编码、属于该组织的任何事件以及该事件的邮政编码的结果。我尝试了各种加入、加入和选择组合，但均无济于事。这是可能的吗？（我可以为 Org Address 和 Event Address 创建一个单独的表，但似乎应该可以只使用一个表）

我的表结构：

mysql> DESCRIBE cc_organisations;
+-------------+------------------+------+-----+---------+----------------+
| Field       | Type             | Null | Key | Default | Extra          |
+-------------+------------------+------+-----+---------+----------------+
| id          | int(10) unsigned | NO   | PRI | NULL    | auto_increment |
| user_id     | int(10) unsigned | NO   | MUL | NULL    |                |
| type        | enum('C','O')    | YES  |     | NULL    |                |
| name        | varchar(150)     | NO   | MUL | NULL    |                |
| description | text             | YES  |     | NULL    |                |
+-------------+------------------+------+-----+---------+----------------+
5 rows in set (0.00 sec)

mysql> DESCRIBE cc_events;
+-------------+------------------+------+-----+---------+----------------+
| Field       | Type             | Null | Key | Default | Extra          |
+-------------+------------------+------+-----+---------+----------------+
| id          | int(10) unsigned | NO   | PRI | NULL    | auto_increment |
| org_id      | int(10) unsigned | NO   | MUL | NULL    |                |
| name        | varchar(150)     | NO   | MUL | NULL    |                |
| start_date  | int(11)          | NO   | MUL | NULL    |                |
| end_date    | int(11)          | YES  | MUL | NULL    |                |
| start_time  | int(11)          | NO   |     | NULL    |                |
| end_time    | int(11)          | NO   |     | NULL    |                |
| description | text             | YES  |     | NULL    |                |
+-------------+------------------+------+-----+---------+----------------+
8 rows in set (0.00 sec)

mysql> DESCRIBE cc_addresses;
+--------------+------------------+------+-----+---------+----------------+
| Field        | Type             | Null | Key | Default | Extra          |
+--------------+------------------+------+-----+---------+----------------+
| id           | int(10) unsigned | NO   | PRI | NULL    | auto_increment |
| org_id       | int(10) unsigned | YES  | MUL | NULL    |                |
| event_id     | int(10) unsigned | YES  | MUL | NULL    |                |
| post_code    | varchar(7)       | NO   | MUL | NULL    |                |
| address_1    | varchar(100)     | NO   |     | NULL    |                |
| address_2    | varchar(100)     | YES  |     | NULL    |                |
| town         | varchar(50)      | NO   |     | NULL    |                |
| county       | varchar(50)      | NO   |     | NULL    |                |
| email        | varchar(150)     | NO   |     | NULL    |                |
| phone        | int(11)          | YES  |     | NULL    |                |
| mobile       | int(11)          | YES  |     | NULL    |                |
| website_uri  | varchar(150)     | YES  |     | NULL    |                |
| facebook_uri | varchar(250)     | YES  |     | NULL    |                |
| twitter_uri  | varchar(250)     | YES  |     | NULL    |                |
+--------------+------------------+------+-----+---------+----------------+
14 rows in set (0.00 sec)
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2 回答 2

2 
select o.Name, oAddress.PostCode, e.Name, eAddress.PostCode 
from cc_organisations o
inner join cc_addresses oAddress on oAddress.org_id = o.id
left outer join cc_events e on e.org_id=o.id
inner join cc_addresses eAddress on eAddress.event_id = e.id
于 2012-04-03T13:48:05.703 回答
0 
 SELECT cco.name as OrgName, cca.post_code as OrgPostCode, cce.id,
        cce.org_id, cce.name, cce.start_date, cce.end_date, cce.start_time,
        cce.end_time, cce.description
 FROM   cc_events cce, cc_addresses cca, cc_organisations cco
 WHERE  cca.event_id = cce.id AND cco.id=cce.org_id 
 ORDER BY cce.start_date
 LIMIT 50;

您可以更改排序和限制，我只是添加了这些，因为我不知道您的数据库有多大......您甚至可以逃脱：

SELECT cco.name as OrgName, cca.post_code as OrgPostCode, cce.*
FROM cc_events cce, cc_addresses cca, cc_organisations cco
WHERE  cca.event_id = cce.id AND cco.id=cce.org_id
ORDER BY cce.start_date LIMIT 50;

但我不是 100% 确定第二个查询是否会失败。

您的address表格中有邮政编码；但它也有组织 ID 和事件 ID 外键。我们只需要检查表中的event_id，address因为任何事件都属于一个组织。

  • 地址的事件匹配事件 ID
  • 活动组织匹配的组织 ID
于 2012-04-03T13:48:13.213 回答