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我有一个名为的表cards，其中包含相关表brigades和identifiers. 一张卡片可以有多个旅和标识符。我想进行单一搜索，例如'purple king'“紫色”是一个旅，“国王”是一个标识符，并找到带有这些旅和标识符的卡片。这个对类似问题的回答https://stackoverflow.com/a/9951200/633513展示了如何跨多个表进行全文搜索。我想做同样的事情，除了我只想要相关的比赛。这可能吗？

表结构：

Cards: id as INT, title as VARCHAR(50)
Brigades: id as INT, brigade as VARCHAR(50)
Identifier: id as INT, identifier as VARCHAR(50)

加入表：

CardBrigades: id as INT, card_id as INT, brigade_id as INT
CardIdentifiers: id as INT, card_id as INT, identifier_id as INT

样本标识符：

Angel
Animal
Archer
Army
Assyrian
Babylonian
Based on Prophecy
Beast
Bows, Arrows, Spears, Javelins and Darts
Canaanite
'Capture' in Special Ability
'Censer' in Title
Chief Priest
Child of Leah
Commander
Connected to David
Connected to Demons
'Covenant' in Title
'David' in Title
'David' in Verse
Deacon
Prince

样本旅：

None
Black
Brown
Crimson
Gold (Evil)
Gray
Orange
Pale Green
Multi (Evil)
Blue
Gold (Good)
Green
Purple
Red
Silver
Teal
White
Multi (Good)
Multi
4

2 回答 2

1

根据您发布的链接中的答案，您可以执行以下操作

SELECT id,SUM(relevance) as total_relevance FROM (
SELECT 
    id, 
    (MATCH(title) AGAINST ('search string')) AS relevance
    FROM Cards
UNION
SELECT 
    Cards.id,
    (MATCH(brigade) AGAINST ('search string')) AS relevance
    FROM Brigades 
    INNER JOIN CardBrigades ON Brigades.id=brigade_id
    INNER JOIN Cards ON card_id=Cards.id 
UNION
SELECT 
    Cards.id,
    (MATCH(identifier) AGAINST ('search string')) AS relevance
    FROM Identifier 
    INNER JOIN CardIdentifier ON Identifier.id=identifier_id
    INNER JOIN Cards on card_id=Cards.id 
) AS combined_search 
GROUP BY id
HAVING total_relevance > 0

我不确定这会表现如何。您可能最好看看其他解决方案，例如 Solr、Lucene 甚至 NoSQL 存储引擎。

于 2012-03-31T08:46:00.983 回答
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如果您只想要相关（相关？）结果，您可以在 BOOLEAN MODE 中使用 FULLTEXT 搜索，如下所示：

select 
    identifier, brigade, P.id as identifier_id, B.id as brigade_id, 
    match(identifier)  against ('purple prince') +
    match(brigade)     against ('purple prince')   as score
from Identifier P, Brigade B
where 
    match(identifier)  against ('purple prince' IN BOOLEAN MODE) and 
    match(brigade)     against ('purple prince' IN BOOLEAN MODE)
order by -score
;

（为简单起见，我只显示查询的 FULLTEXT 搜索部分并省略与 Card* 表的连接）

于 2013-10-12T07:53:18.743 回答