1

全部，

我有一个方法，它从数据库中获取一个日期（YYYY-MM-DD H:M:S），并从日期字符串中创建一个包含年、月和日组件的 URL。我的解决方案有效，但我想知道是否有更好的方法来做到这一点？酷孩子们是怎么做到的？:-)

谢谢！

   -(NSString *) prettyURLFrom:(NSString *)dateString{



    NSString * URLString = @"";
    NSString *URL = @"http://www.theblues.com/featured/article/";

    NSArray *myWords = [dateString componentsSeparatedByCharactersInSet:
                        [NSCharacterSet characterSetWithCharactersInString:@"-\" \" :"]
                        ];


    URLString = [NSString stringWithFormat:@"%@%@/%@/%@", 
                    URL,
                    [myWords objectAtIndex:1],
                    [myWords objectAtIndex:2],
                    [myWords objectAtIndex:0]];



    return URLString;


   }
4

2 回答 2

1

如果你有NSDate对象，那么你可以使用 

NSDateComponents *components = [[NSCalendar currentCalendar] components:NSDayCalendarUnit | NSMonthCalendarUnit | NSYearCalendarUnit fromDate:date];

    NSInteger day = [components day];
    NSInteger month = [components month];
    NSInteger year = [components year];

NSString 到 NSDate

[NSDateFormatter setDefaultFormatterBehavior:NSDateFormatterBehavior10_4];
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:@"YYYY-MM-DD HH:MM:SS"];

NSDate *dateFromString = [[NSDate alloc] init];
dateFromString = [dateFormatter dateFromString:@"1999-07-02 2:2:4"];
于 2012-03-30T12:10:41.740 回答
1

就像我在评论中所说的那样，我觉得奇怪的是，当它们可能应该分别是 NSDate 和 NSURL 时，你将值作为字符串传递和返回。

我可能会做类似的事情：

-(NSURL*)URLFromDate:(NSDate*)date
{
    // Assumes user uses a gregorian calendar
    NSDateComponents *dateComp = [[NSCalendar currentCalendar] components:(NSYearCalendarUnit | NSMonthCalendarUnit |  NSDayCalendarUnit) fromDate:date];

    return [NSURL URLWithString:[NSString stringWithFormat:@"http://www.theblues.com/featured/article/%li/%li/%li"
                                    , [dateComp year]
                                    , [dateComp month]
                                    , [dateComp day]]];
}
于 2012-03-30T12:23:34.137 回答