0

在下面的代码中,当 _uiChkTestAction 和 _uiChkTestItem JCheckBox 都未选中时,单击 bu1 按钮使它们都选中,但单击 bu2 按钮不会将 _uiChkTestItem JCheckBox 从未选中变为选中。

那么,我的代码有问题吗?

import javax.swing.*;
import java.awt.*;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.awt.event.ItemEvent;
import java.awt.event.ItemListener;

public class TestActionItemListener
{
public static void main(String[] _args)
{
    EventQueue.invokeLater(new Runnable(){

    public void run(){

    JFrame _fra = new JFrame("Testing");
    _fra.setSize(500, 500);
    _fra.setLayout(new FlowLayout());
    final JCheckBox _uiChkTestAction = new JCheckBox("ActionListener");
    _uiChkTestAction.addActionListener(new ActionListener()
    {
        public void actionPerformed(ActionEvent _ev)
        {
            System.out.println("State by ActionListener: " + _uiChkTestAction.isSelected());
        }
    });

    final JCheckBox _uiChkTestItem = new JCheckBox("ItemListener");
    _uiChkTestItem.addItemListener(new ItemListener()
    {
        public void itemStateChanged(ItemEvent e)
        {
            System.out.println("State by ItemListener: " + _uiChkTestAction.isSelected());
        }
    });
    JButton bu1 = new JButton("actionlistener bu");
    bu1.addActionListener(new ActionListener(){

        @Override
        public void actionPerformed(ActionEvent e) {
          _uiChkTestAction.setSelected(true);
        }
     });
    JButton bu2 = new JButton("itemlistener bu");
    bu1.addActionListener(new ActionListener(){

        @Override
        public void actionPerformed(ActionEvent e) {
        _uiChkTestItem.setSelected(true);
        }
     });
    _fra.add(_uiChkTestAction);
    _fra.add(_uiChkTestItem);
    _fra.add(bu1);
    _fra.add(bu2);
    _uiChkTestAction.setSelected(true);
    _uiChkTestItem.setSelected(true);

    _fra.setVisible(true);
}}
);
}
};
4

2 回答 2

3

您将两个侦听器都添加到同一个按钮bu1iso 中添加一个 tobu1和一个 tobu2

于 2012-03-27T12:26:46.750 回答
1

您要添加一个侦听器bu1两次。将第二个添加到bu2.

于 2012-03-27T12:27:30.830 回答