我不太了解get_comment_permalinkDjango 的评论框架。
我使用 Django 的评论为我的班级创建了一些评论Order，默认情况下它显示类似的 url，/comments/cr/18/1/#c1并且该 url 永远不存在。
我看了评论urls.py，上面写着
urlpatterns += patterns('',
url(r'^cr/(\d+)/(.+)/$', 'django.contrib.contenttypes.views.shortcut', name='comments-url-redirect'),
)
views.py有shortcut方法的是
from django import http
from django.contrib.contenttypes.models import ContentType
from django.contrib.sites.models import Site, get_current_site
from django.core.exceptions import ObjectDoesNotExist
from django.utils.translation import ugettext as _
def shortcut(request, content_type_id, object_id):
"""
Redirect to an object's page based on a content-type ID and an object ID.
"""
# Look up the object, making sure it's got a get_absolute_url() function.
try:
content_type = ContentType.objects.get(pk=content_type_id)
if not content_type.model_class():
raise http.Http404(_(u"Content type %(ct_id)s object has no associated model") %
{'ct_id': content_type_id})
obj = content_type.get_object_for_this_type(pk=object_id)
except (ObjectDoesNotExist, ValueError):
raise http.Http404(_(u"Content type %(ct_id)s object %(obj_id)s doesn't exist") %
{'ct_id': content_type_id, 'obj_id': object_id})
try:
get_absolute_url = obj.get_absolute_url
except AttributeError:
raise http.Http404(_("%(ct_name)s objects don't have a get_absolute_url() method") %
{'ct_name': content_type.name})
absurl = get_absolute_url()
# Try to figure out the object's domain, so we can do a cross-site redirect
# if necessary.
# If the object actually defines a domain, we're done.
if absurl.startswith('http://') or absurl.startswith('https://'):
return http.HttpResponseRedirect(absurl)
# Otherwise, we need to introspect the object's relationships for a
# relation to the Site object
object_domain = None
if Site._meta.installed:
opts = obj._meta
# First, look for an many-to-many relationship to Site.
for field in opts.many_to_many:
if field.rel.to is Site:
try:
# Caveat: In the case of multiple related Sites, this just
# selects the *first* one, which is arbitrary.
object_domain = getattr(obj, field.name).all()[0].domain
except IndexError:
pass
if object_domain is not None:
break
# Next, look for a many-to-one relationship to Site.
if object_domain is None:
for field in obj._meta.fields:
if field.rel and field.rel.to is Site:
try:
object_domain = getattr(obj, field.name).domain
except Site.DoesNotExist:
pass
if object_domain is not None:
break
# Fall back to the current site (if possible).
if object_domain is None:
try:
object_domain = get_current_site(request).domain
except Site.DoesNotExist:
pass
# If all that malarkey found an object domain, use it. Otherwise, fall back
# to whatever get_absolute_url() returned.
if object_domain is not None:
protocol = request.is_secure() and 'https' or 'http'
return http.HttpResponseRedirect('%s://%s%s'
% (protocol, object_domain, absurl))
else:
return http.HttpResponseRedirect(absurl)
这对我来说太复杂了，我无法理解。
当 Django 说永久链接时，我会考虑引用页面上的特定位置（通常是标题）。例如，Django 的评论框架文档是链接 #1，您可以使用链接 #2 永久链接“链接到评论”部分。
1. https://docs.djangoproject.com/en/dev/ref/contrib/comments/
2. https://docs.djangoproject.com/en/dev/ref/contrib/comments/#linking-to-comments
所以对于评论，不应该是一样的吗？URL 不应该只是 a#c1或没有 的东西/comments/cr/18/1/...吗？实际上我什至不知道 Django 从哪里得到18and 1... 从shortcut方法中，我知道18是content_type_idand1是object_id，但是我怎么知道哪个类models.py是哪个内容类型 id 和对象 id？