php - 如何在 PHP 中以不同方式替换相同的值

Question

我有一个这样的立陶宛语变格代码：

<?php
    $word               = "namas";
    $string             = str_repeat("$word ", 4);
    $patterns           = array();
    $patterns[0]        = '/as/';
    $patterns[1]        = '/as/';
    $patterns[2]        = '/as/';
    $patterns[3]        = '/as/';
    $replacements       = array();
    $replacements[0]    = 'as';
    $replacements[1]    = 'o';
    $replacements[2]    = 'ui';
    $replacements[3]    = 'a';
    ksort($patterns);
    ksort($replacements);
    echo preg_replace($patterns, $replacements, $string);
?>

我怎么能以不同的方式更换？我想要这样的结果： namas namo namui nama 但我到处都有“namo namo namo”。

Answer 1

像循环一样思考，

1. 更改as为as，字符串变为“namas namas namas namas”
2. 更改as为o字符串变为“namo namo namo namo”
3. 更改as为ui不匹配（'namo namo namo namo'仍然存在）
4. 更改as为o不匹配（'namo namo namo namo'仍然存在）

Answer 2

这就是我认为你想要的：

<?php
$word ="namas";
$patterns = array();
$patterns[0] = '/as/';
$patterns[1] = '/as/';
$patterns[2] = '/as/';
$patterns[3] = '/as/';

$replacements = array();
$replacements[0] = 'as';
$replacements[1] = 'o';
$replacements[2] = 'ui';
$replacements[3] = 'a';

ksort($patterns);
ksort($replacements);

foreach ($patterns as $idx => $pat)
{
    echo " " . preg_replace ($pat, $replacements[$idx], $word);
}

?>

进一步简化为：

<?php
$word ="namas";
$pattern = '/as/';

$replacements = array();
$replacements[0] = 'as';
$replacements[1] = 'o';
$replacements[2] = 'ui';
$replacements[3] = 'a';

foreach ($replacements as $replace)
{
    echo " " . preg_replace ($pattern, $replace, $word);
}

?>