r - 使用 XLConnect 将列表名称用作工作表的名称

Question

正如标题所示，我想做上面的事情。下面的例子：

library(stringr)
library(XLConnect)

df <- data.frame(do.call("rbind", lapply(1:10, function(i) rnorm(10))))
df.list <- rep(list(df), 10)
names(df.list) <- paste("DataFrame", str_pad(1:length(df.list), 2, pad = "0"), sep = "")

df.list.workbook <- loadWorkbook("df.list.workbook.xlsx", create = TRUE)
lapply(1:length(df.list), function(i) createSheet(df.list.workbook, name = names(df.list[i])))
lapply(df.list[1:length(df.list)], function(i) writeWorksheet(df.list.workbook, i, sheet = names(i)))

最后一行是它引发错误的地方：

Error: IllegalArgumentException (Java): Sheet index (-1) is out of range (0..9)

为了解决这个问题，我尝试了：

lapply(df.list[1:length(df.list)], function(i) print(names(i)))

并意识到列的名称被传递给工作表变量。任何想法如何克服这个问题？

Answer 1

您需要lapply覆盖索引而不是列表：

lapply(seq_along(df.list), function(i) writeWorksheet(df.list.workbook, df.list[[i]], sheet = names(df.list)[i]))

Answer 2

XLConnect 在很多地方都被矢量化了。在您的情况下，这适用于createSheetand writeWorksheet，因此您可以编写：

df.list.workbook <- loadWorkbook("df.list.workbook.xlsx", create = TRUE)
createSheet(df.list.workbook, name = names(df.list))
writeWorksheet(df.list.workbook, data = df.list, sheet = names(df.list))
saveWorkbook(df.list.workbook)