5

我已经上交了，所以你不会帮我作弊。只是想知道这是否正确：

作业：输入员工姓名和工资列表，并确定平均（平均）工资以及高于和低于平均值的工资数量。

计划：允许输入姓名和薪水 计算平均值 排序值 计数值高于平均值 计数值低于平均值

//This program will allow a user to input an employee name and salary
//The output will contain the mean salary 
//as well as the number of salaries above and below the mean
//
//Arrays Used:
//Name(K) = Array for employee names
//Salary(K) = Array for salaries
//
//Variables Used:
//Mean = Mean of all employees Salaries
//UpMean = Number of Employees making more than the mean
//DwnMean = Number of Employees making less than the mean
//Sum = Sum of all salaries
//CountM = Counter for Mean
//CountUp = Counter for # of salaries above mean
//CountDwn = Counter for # of salaries below mean

Main
    Call WelcomeMessage
    Call InputData
    Call Calculate
    Call OutputData
End Program

WelcomeMessage
    Write, “Beginning the Salary Program” 
End WelcomeMessage

InputData
    Declare Name(100) Of Strings
    Declare Salary(100) Of Real
    Declare Mean, UpMean, DwnMean As Real
    Set Sum = 0
    Set CountM = 0
    Set CountUp = 0
    Set CountDwn = 0
    Write, "Enter Employee name and Salary."
    Write, "Enter *,0 when done."
    Input Name(K), Salary(K)
    While Name(K) <> "*"
        Set CountM = CountM + 1
        Set Sum = Sum + Salary
        Write, "Enter Employee name and Salary."
        Write, "Enter *,0 when done."
        Input Name(K), Salary(K)
    End While
End InputData

Calculation
    //Here Mean is found
    Set Mean = Sum / CountM
    //Here Number of Employees making more than the mean is found
    For K = Step 1 to CountM
        If Salary(K) > Mean Then
            Set CountUp = CountUp + 1
        End If
    //Here Number of Employees making more than the mean is found
    Set CountDwn = CountM - CountUp
    //The above algorythm doesn't account for the possibility 
    //of someone making exactly the average so subtract 1 to reconcile
    If Salary(K) = Mean Then
            Set CountDwn = CountDwn - 1
    End If
End Calculation

OutputData
    Write, "There were,"  CountM, "salaries entered."
    Write, "The mean salary is:", Mean
    Write, "There are", CountUp, "employees who make more than the average"
    Write, "There are", CountDwn, "employees who make less than the average"
End OutputData
4

3 回答 3

5

看起来还可以。我唯一要建议的是，在读取姓名/销售额的输入时使用 do-while 结构。如您所见，在循环开始之前和循环中，您具有相同的逻辑：

Write, "Enter Employee name and Salary."
Write, "Enter *,0 when done."
Input Name(K), Salary(K)

此外，伪代码将无法编译，因为您正在调用 Calculate 但例程称为 Calculation ;)

感谢您的建议。对 Do-While 还不是很熟悉。那会是什么样子？我虽然可能有关输入的某些内容应该在循环中更改，但不确定如何更改。

它可能看起来像这样：

Do 
    Write, "Enter Employee name and Salary."
    Write, "Enter *,0 when done."
    Input Name(K), Salary(K)
    If Name(K) <> "*"
        Set CountM = CountM + 1
        Set Sum = Sum + Salary
    Else
        BreakLoop
    End If
End While (true)

差别不大，其实更多的是口味问题。我个人认为它更容易阅读，因为代码的编写方式使您很容易意识到您应该输入一些东西，检查输入并根据输入做一些事情。

在您的 while 循环中，Set CountM 等出现在（在文本流中）第一个输入之后，但在输入的其余部分之前，这意味着您必须回顾循环的顶部以了解它在前一个输入之后做了什么循环中的“圆”。现在这只是一个小循环，但如果它是 30 行长（上帝保佑），你必须向上滚动才能看到发生了什么。如果你明白我的意思 ：）

于 2009-06-11T23:12:21.347 回答
1

关于计算的注意事项CountDwn：

您的“减 1 以协调”将取决于For循环在实现语言中的工作方式，（a）生成“未声明的变量”类型错误，（b）生成“索引超出范围”错误，或（c ) 减去一个 IFF，最后的工资正好等于平均值​​。（此外，您的代码不包含End Forin Calculation，但我认为它应该紧跟End If在该函数中的第一个之后。）

我建议不要计算CountDwn（CountUp毕竟，每个薪水都可能等于平均值​​），我建议将其包含在循环中：

Calculation
    //Here Mean is found
    Set Mean = Sum / CountM

    For K = Step 1 to CountM
        //Here Number of Employees making more than the mean is found
        If Salary(K) > Mean Then
            Set CountUp = CountUp + 1
        End If

        //Here Number of Employees making less than the mean is found
        If Salary(K) < Mean Then
            Set CountDwn = CountDwn + 1
        End If
    End For
End Calculation

注意CountUp + CountDwn不一定等于CountM。

于 2009-06-11T23:50:43.470 回答
0 
FINAL ALGORITHM

START
OUTPUT "Enter the number of parcels"
INPUT NUMBEROFPARCELS
INTEGER PRICE = 0
INTEGER PARCELWEIGHT [1:NUMBEROFPARCELS]
INTEGER TOTALPRICE = 0

FOR PARCELLOOP = 1 TO NUMBEROFPARCELS
    INTEGER REJECT = 0
    INTEGER ACCEPT = 0
    INTEGER ACCEPTWEIGHT = 0
    INTEGER REJECTEDPARCELS = 0

    OUTPUT "Enter the weight of the parcel in kg"
    INPUT WEIGHT
    IF (WEIGHT < 1) THEN
        REJECT = REJECT + 1
        OUTPUT "The weight of the parcel should be atleast 1kg"
    ELSE
        IF (WEIGHT > 10) THEN
            REJECT = REJECT + 1
            OUTPUT "The weight of the parcel should be less than 10kg"
    ENDIF
    IF (WEIGHT > 1) THEN
        IF (WEIGHT < 10) THEN
            PARCELWEIGHT[PARCELLOOP] = WEIGHT
        ENDIF
    ENDIF


    OUTPUT "Enter the first dimension of the parcel in cm"
    INPUT DIMENSION1
    IF (DIMENSION1 > 80 ) THEN
        REJECT = REJECT + 1
        OUTPUT "Each dimension of the parcel should be less than 80"
    ENDIF

    OUTPUT "Enter the second dimension of the parcel in cm"
    INPUT DIMENSION2
    IF (DIMENSION2 > 80 ) THEN
        REJECT = REJECT + 1
        OUTPUT "Each dimension of the parcel should be less than 80"
    ENDIF

    OUTPUT "Enter the third dimension of the parcel in cm"
    INPUT DIMENSION3
    IF (DIMENSION3 > 80 ) THEN
        REJECT = REJECT + 1
        OUTPUT "Each dimension of the parcel should be less than 80"
    ENDIF

    TOTALDIMENSION = DIMENSION1 + DIMENSION2 + DIMENSION3
    IF (TOTALDIMENSION > 200 ) THEN
        REJECT = REJECT + 1
        OUTPUT "The size of the parcel should be less than 200cm"
    ENDIF

    IF (REJECT > 0 ) THEN
        OUTPUT "Your parcel has been rejected for the reasons above"
        REJECTEDPARCELS = REJECTEDPARCELS + 1
    ENDIF

    IF (REJECT = 0)THEN
        OUTPUT "Your parcel has been accepted"
        ACCEPT = ACCEPT + 1 
        ACCEPTWEIGHT = ACCEPTWEIGHT + WEIGHT
    END IF

    INTEGER PARCELSACCEPTED = ACCEPT
    INTEGER TOTALWEIGHT = ACCEPTWEIGHT
    INTEGER PARCELSREJECTED = REJECTEDPARCELS

    OUTPUT "The number of parcels accepted is " PARCELSACCEPTED " and the total weight of the parcels is " TOTALWEIGHT
    OUTPUT "The number of parcels rejected is " PARCELSREJECTED
NEXT PARCELLOOP

FOR PRICELOOP = 1 TO NUMBEROFPARCELS
    IF (PARCELWEIGHT[PARCELLOOP] < 5) THEN
        PRICE = PRICE + 10
        TOTALPRICE = TOTALPRICE +PRICE
    END IF

    IF (PARCELWEIGHT[PARCELLOOP] > 5) THEN
        PRICE = ((PARCELWEIGHT[PARCELLOOP] - 5)*0.10)/100
        TOTALPRICE = TOTALPRICE +PRICE
    END IF

    OUTPUT "The price of the parcel is " PRICE
NEXT PRICELOOP

OUTPUT "The total price of all the parcels is " TOTALPRICE
STOP
于 2016-11-13T04:29:43.000 回答