1

我目前无法在正在生成的表中查找按钮的索引/位置。

private class Node
   {
    String id;
    String[] data;
    List<Node> children = new ArrayList<Node>();
}

private Node root = buildTree();

private Node buildTree()
    {
        Node root = new Node();
        root.id = "Main Component";
        root.data = new String[]{ "example", "example", "example", "example", "example", "example",};

    Node child1 = new Node();
    child1.id = "Part 1";
    child1.data = new String[]{ "example", "example", "example", "example", "example", "example", "example"};
    root.children.add(child1);

    Node child11 = new Node();
    child11.id = "Part 1-1";
    child11.data = new String[]{ "example", "example", "example", "example", "example", "example", "example"};
    child1.children.add(child11);

    Node child2 = new Node();
    child2.id = "Part 2";
    child2.data = new String[]{ "example", "example", "example", "example", "example", "example", "example"};
    root.children.add(child2);

    Node child21 = new Node();
    child21.id = "Part 2-1";
    child21.data = new String[]{ "example", "example", "example", "example", "example", "example", "example"};
    child2.children.add(child21);

    Node child22 = new Node();
    child22.id = "Part 2-2";
    child22.data = new String[]{ "example", "example", "example", "example", "example", "example", "example"};
    child2.children.add(child22);

    Node child3 = new Node();
    child3.id = "Part 3";
    child3.data = new String[]{ "example", "example", "example", "example", "example", "example", "example"};
    root.children.add(child3);

    Node child31 = new Node();
    child31.id = "Part 3-1";
    child31.data = new String[]{ "example", "example", "example", "example", "example", "example", "example"};
    child3.children.add(child31);

    Node child32 = new Node();
    child32.id = "Part 3-2";
    child32.data = new String[]{ "example", "example", "example", "example", "example", "example", "example"};
    child3.children.add(child32);

    return root;
}

这是我的数据模型。这里的想法是我将使用几个函数向表中添加行，但是我被困在了早期阶段。

private void addRow(Node nde)
{
    HorizontalPanel buttonPanel = new HorizontalPanel();

    ListBox comboBox = new ListBox();
    comboBox.addItem("option1");
    comboBox.addItem("option2");
    comboBox.addItem("option3");
    comboBox.addItem("option4");
    comboBox.addItem("option5");

    Button addRowButton = new Button("+/-");

    addRowButton.addClickHandler(new ClickHandler() {
        public void onClick(ClickEvent event) {
            //Get the button from the click event
            //Get the row from the button - could I possibly set a class to each button that equals the id of the element being added so that I could just pull the id from the button
            //Use the row to get the first column - returns a panel
            //Get the components on the panel, find the label, and get the text
            String id = "";
            clickFunction(id);
        }
    });

    buttonPanel.add(addRowButton);
    buttonPanel.add(new Label(nde.id));

    int row = flexTable.getRowCount();
    flexTable.setWidget(row,0,buttonPanel);
    flexTable.setWidget(row,1,comboBox);
    flexTable.setText(row,2,nde.data[0]);
    flexTable.setText(row,3,nde.data[1]);
    flexTable.setText(row,4,nde.data[2]);
    flexTable.setText(row,5,nde.data[3]);
    flexTable.setText(row,6,nde.data[4]);
    flexTable.setText(row,7,nde.data[5]);
}

这就是我添加行的方式，每行的第一列中有一个水平面板，第一个元素是一个按钮，第二个元素是与该行中显示的任何节点的 ID 匹配的标题。我需要一种方法来获取该 ID，将其设置为等于字符串并将其传递给我的 clickFunction。

private void clickFunction(String curRowId)
{
    Node rowNode = findNode(root, curRowId);

            //need to determine whether or not the tree needs to be expanded or minimized.

            for(Node n : rowNode.children) {
        addRow(n);
    }

}

clickFunction 使用我的 findNode 函数中传递的 id

private Node findNode(Node nde, String id)
{
    if(nde.id.equals(id))
    {
        return nde;
    }

    for(Node n : nde.children)
    {
        Node rtrn = findNode(n, id);
        if(rtrn != null)
        {
            return rtrn;
        }
    }

    return null;
}

递归调用它来告诉代码哪个节点需要扩展其子节点。我希望这不会太长，我想确保我包含所有相关信息并证明我实际上正在努力解决我遇到的问题。当我做了这么多工作却无法解决一个看似简单的问题时，这绝对令人沮丧。

非常感谢任何信息！非常感谢提前！

4

1 回答 1

0

要设置按钮的 id，您可以执行以下操作...

Button b = new Button();
DOM.setElementAttribute(b.getElement(), "id", "my-button-id");

然后，您应该能够在您的 findNode 方法中匹配它。

有关使用 DOM 的更多信息，请参阅http://google-web-toolkit.googlecode.com/svn/javadoc/1.5/com/google/gwt/user/client/DOM.html。

于 2012-03-23T12:44:24.810 回答