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我正在尝试使用以下 INTERSECT 查询来查询我的 Android SQLite 数据库，但它崩溃了。这两个选择查询本身就可以正常工作，并且它们肯定会产生匹配的结果，所以我不明白为什么 INTERSECT 语句不起作用：

SQLiteDatabase db = (new DatabaseHelper(this)).getWritableDatabase();
Cursor cursor = db.rawQuery("SELECT tblsyndromes._id, synname" +
"  FROM tblsyndromes JOIN tblsymsynlink ON tblsymsynlink.synId =      tblsyndromes._id" +
" WHERE tblsymsynlink.symId = "+intCondition+" " +
" INTERSECT SELECT tblsyndromes._id, synname FROM tblsyndromes JOIN synconlink" +
" ON synconlink.synId = tblsyndromes._id" +
" WHERE synconlink.conId = "+intCondition2+"", null);

我正在使用的新代码 -

String sqlString = "SELECT tblsyndromes._id, tblsyndromes.synname FROM tblsyndromes       JOIN synconlink ON synconlink.synId = tblsyndromes._id WHERE synconlink.conId = 55 INTERSECT SELECT tblsyndromes._id, tblsyndromes.synname FROM tblsyndromes JOIN tblsymsynlink ON tblsymsynlink.synId = tblsyndromes._id WHERE tblsymsynlink.symId = 136";

SQLiteDatabase db = (new DatabaseHelper(this)).getWritableDatabase();

Cursor cursor = db.rawQuery(sqlString,null);

ArrayList<String> mArrayList = new ArrayList<String>();
cursor.moveToFirst();
while(!cursor.isAfterLast()) {
     mArrayList.add(cursor.getString(cursor.getColumnIndex("synname")));
     cursor.moveToNext();
}

我已经使用 sqlite3 反复测试了 sql 并且它可以工作 - 两个选择查询在 android 中独立工作但是一旦我尝试使用 INTERSECT 我就会崩溃 - 我现在收到以下错误

对字段槽 0,-1 的错误请求。numRows = 3，numColumns = 2

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1 回答 1

-1 
public Long insert_todoinfo(String a, String b, String c, String d,
            String e, String f, String g) {
        // TODO Auto-generated method stub
        ContentValues con = new ContentValues();
        con.put("title", a);
        con.put("description", b);
        con.put("category", e);
        con.put("due_date", c);
        con.put("alarm_time", d);
        con.put("alarm_set", f);
        con.put("priority", g);
        con.put("parform", "false");
        return mDb.insert(DATABASE_TABLE_TODO_LIST, null, con);
    }
于 2012-03-22T12:30:14.753 回答