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我想通过标签名称和属性名称来比较两个（或更多）XML 文件。我对属性或节点的值不感兴趣。

在谷歌上搜索我发现 XMLDiff 补丁（http://msdn.microsoft.com/en-us/library/aa302294.aspx），但它对我不起作用......或者我不知道如何进行设置工作为了我。文件 A

    <info>
  <Retrieve>
    <LastNameInfo>
      <LNameNum attribute="some_val">1</LNameNum>
      <NumPeople>1</NumPeople>
      <NameType/>
      <LName>TEST</LName>
    </LastNameInfo>
    <Segment>
      <SegNum>1</SegNum>
      <Comment>A test</Comment>
    </Segment>
    <Segment>
      <SegNum>2</SegNum>
      <Dt>20110910</Dt>
      <Comment>B test</Comment>
    </Segment>
  </Retrieve>
</info>

文件 B

<info>
  <Retrieve>
    <LastNameInfo>
      <LNameNum attribute="other_val">4</LNameNum>
      <NumPeople>1</NumPeople>
      <NameType/>
      <LName>TEST7</LName>
    </LastNameInfo>
    <Segment>
      <SegNum>1</SegNum>
      <Comment>A test</Comment>
    </Segment>
    <Segment>
      <SegNum>2</SegNum>
      <Dt>20110910</Dt>
      <Comment>B test</Comment>
    </Segment>
  </Retrieve>
</info>

这两个文件必须相等。

谢谢！

4

1 回答 1

1

Well if you'd like to do this "manually" an idea would be to use a recursive function and loop through the xml structure. Here is a quick example:

var xmlFileA = //first xml
var xmlFileb = // second xml

var docA = new XmlDocument();
var docB = new XmlDocument();

docA.LoadXml(xmlFileA);
docB.LoadXml(xmlFileb);

var isDifferent = HaveDiferentStructure(docA.ChildNodes, docB.ChildNodes);
Console.WriteLine("----->>> isDifferent: " + isDifferent.ToString());

This is your recursive function:

private bool HaveDiferentStructure(
            XmlNodeList xmlNodeListA, XmlNodeList xmlNodeListB)
{
    if(xmlNodeListA.Count != xmlNodeListB.Count) return true;                

    for(var i=0; i < xmlNodeListA.Count; i++)
    {
         var nodeA = xmlNodeListA[i];
         var nodeB = xmlNodeListB[i];

         if (nodeA.Attributes == null)
         {
              if (nodeB.Attributes != null)
                   return true;
              else
                   continue;
         }

         if(nodeA.Attributes.Count != nodeB.Attributes.Count 
              || nodeA.Name != nodeB.Name) return true;

         for(var j=0; j < nodeA.Attributes.Count; j++)
         {
              var attrA = nodeA.Attributes[j];
              var attrB = nodeB.Attributes[j];

              if (attrA.Name != attrB.Name) return true;
          }

          if (nodeA.HasChildNodes && nodeB.HasChildNodes)
          {
              return HaveDiferentStructure(nodeA.ChildNodes, nodeB.ChildNodes);
          }
          else
          {
              return true;
          }
     }
     return false;
}

Please keep in mind that this will only return true as long as the nodes and attributes are in the same order, and same casing is used on both xml files. You can enhance it to include or exclude attributes/nodes.

Hope it helps!

于 2012-03-17T15:45:07.063 回答