3

再会 。我只是想问一下在给定日期添加天数。我有一个 jtexfield (txtStart) 和另一个 jtexfield(txtExpiry)。我需要在 txtExpiry 中显示自 txtStart 中的日期起 102 天后的日期。我正在使用 KEYRELEASED 事件。我在txtStart中输入后，txtExpiry中会出现额外102天的日期。

这是我的代码，但它仍然是错误的。 

private void txtStartKeyReleased(java.awt.event.KeyEvent evt) {
// TODO add your handling code here:
    // set calendar to 1 Jan 2007
    int a = Integer.parseInt(txtStart.getText());     
    Calendar calendar = new GregorianCalendar(a,a,a);

     calendar.add(Calendar.DAY_OF_MONTH,102);
     PrintCalendar(calendar);
  }

   private void PrintCalendar(Calendar calendar){
        // define output format and print
        SimpleDateFormat sdf = new SimpleDateFormat("yyyy-mm-dd");         
        String date = sdf.format(calendar.getTime());
        long add = Date.parse(date);
        txtExpiry.setText(add);  -----> this part here also has an error.
     }

我的代码仍然不会在 txtExpiry 中生成日期。提前致谢

以下是获得帮助后的正确代码：

 private void txtStartKeyReleased(java.awt.event.KeyEvent evt) {
       try {    

        Date date1;
        date1 = new SimpleDateFormat("yyyy-MM-dd").parse(txtStart.getText());
        System.out.println(date1);

        SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd");     
        Calendar cal  = Calendar.getInstance();
                      cal.setTime(date1);
                        cal.add(Calendar.DATE, 102);
                        String expDateString = sdf.format(cal.getTime());
                        txtExpiry.setText(expDateString);
     }catch (ParseException ex) {
      Logger.getLogger(ClientInfo.class.getName()).log(Level.SEVERE, null, ex);
     } 
}
4

3 回答 3

7

采用

yyyy-MM-dd

注：大写MM

看 ：SimpleDateFormat

现在，一旦你有了日期实例，你就可以用Calendar它来做天数算术

Calendar cal = Calendar.getInstance();
cal.setTime(parsedDate);
cal.add(Calendar.DATE, 102);
String expDateString = dateFormatter.format(cal.getTime());
于 2012-03-13T19:05:18.113 回答
0

一旦你有了正确的格式，你就可以使用JodaTime。您可以使用 JodaTime 直接解析该String值，但既然您已经这样做了，我没有打扰...

Date date = ...;
DateTime dt = new DateTime(date);
dt = dt.plusDays(102);
date = dt.toDate();
于 2015-01-24T02:03:58.507 回答
-1 
import java.util.*;
class ISCprac2009q01{
public static void main(String args[])
throws InputMismatchException{

Scanner scan=new Scanner(System.in);
System.out.println("ENTER DAY NUMER(>=1 AND
 <=366) : ");
int day_number=scan.nextInt();
System.out.println("ENTER YEAR(4 DIGIT) : ");
int year=scan.nextInt();
System.out.println("ENTER DATE AFTER(N)(>=1 AND
 <=100) : ");
int n=scan.nextInt();

if(day_number<1 || day_number>366)
System.out.println("INVALID DAY NUMBER.");
else if(year<1000 || year >9999)
System.out.println("INVALID YEAR");
else if(n<1 || n>100)
System.out.println("INVALID DATE AFTER VALUE.");
else{
//INITIALIZE MONTH NAMES AND NUMBER OF DAYS IN EACH MONTH
    String month_names[]={"JANUARY", "FEBRUARY","MARCH",
        "APRIL","MAY","JUNE","JULY","AUGUST","SEPTEMBER",
        "OCTOBER","NOVERMBER","DECEMBER"};
    int month_days[]={31,28,31,30,31,30,31,31,30,31,30,31};
    int i, day, month,day_after;
    String suffix;

   //IF IT IS A LEAP YEAR FEBRURAY SHOULD HAVE 29 DAYS
    if(year%400==0 || (year%100!=0 && year%4==0))
        month_days[1]=29;

        i=0;
   //FIND THE DATE CORRESPONDING TO THE DAY NUMBER
        day=day_number;
        while(day>month_days[i])
        {
            day-=month_days[i];
            i++;
        }
        month=i;
        //ADD SUFFIX AS PER THE DAY
        if(day%10==1 && day/10!=1)
            suffix="ST";
        else if(day%10==2 && day/10!=1)
            suffix="ND";
        else if(day%10==3 && day/10!=1)
            suffix="RD";
        else
            suffix="TH";
        System.out.println("OUTPUT:");
        //FIRST PART OF THE OUTPUT
        System.out.println(day+suffix+" "+
        month_names[month]+" "+year);

        //TO CALCULATE DATE AFTER N DAYS
        day_after=day_number+n;
        i=0;
        while(day_after>month_days[i])
        {
            day_after-=month_days[i];
            i++;
            if(i==12){
            i=0;
            year++;
            if(year%400==0 || (year%100!=0 && year%4==0))
                month_days[1]=29;
            }
        }
        day=day_after;
        month=i;
        //ADD SUFFIX AS PER THE DAY
        if(day%10==1 && day/10!=1)
            suffix="ST";
        else if(day%10==2 && day/10!=1)
            suffix="ND";
        else if(day%10==3 && day/10!=1)
            suffix="RD";
        else
            suffix="TH";
       //SECOND PART OF THE OUTPUT
        System.out.println(day+suffix+" "+
        month_names[month]+" "+year);
}
}
}
于 2016-02-21T06:55:29.813 回答