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我想在 android 中使用 Google Places API 添加我自己的地方我正在使用以下代码片段，但是它给了我这个例外：

com.google.api.client.http.HttpResponseException: 400 错误请求

我的代码片段是：

private static final String PLACE_ADD_URL = "https://maps.googleapis.com/maps/api/place/add/json?"; 
public PlacesList addPlace() throws Exception {

try {
        Log.v(LOG_KEY, "Adding Place...");
        GenericUrl reqUrl = new GenericUrl(PLACE_ADD_URL);
        reqUrl.put("key", API_KEY);
        reqUrl.put("sensor", "false");
        Log.v(LOG_KEY, "Adding Place...");
        //reqUrl.put("Host:", "maps.googleapis.com");
        reqUrl.put("Host: maps.googleapis.com","{\"location\":{\"lat\":-33.8733721,\"lng\":151.2012871},\"accuracy\":50.0,\"name\":\"harbour\",\"types\":[\"food\"],\"language\":\"en\"}");
        Log.v(LOG_KEY, "Requested URL= " + reqUrl);

        HttpRequestFactory httpRequestFactory = createRequestFactory(transport);
        HttpRequest request = httpRequestFactory.buildGetRequest(reqUrl);


        Log.v(LOG_KEY, request.execute().parseAsString());  
        PlacesList place = request.execute().parseAs(PlacesList.class);

        Log.v(LOG_KEY, "STATUS = " + place.status); 
        Log.v(LOG_KEY, "Place Added is = " + place);    

            return place;

    } catch (HttpResponseException e) {
        Log.v(LOG_KEY, e.getResponse().parseAsString());
        throw e;
    }

    catch (IOException e) {
        // TODO: handle exception
        throw e;
    }
}

现在我玩了很多这个异常但无法解决，我应该如何传递这个请求 URL？我的方法是对还是错？？

4

1 回答 1

0

我将 Key 返回为空。现在我通过了正确的密钥，它工作正常

于 2012-03-14T15:58:30.987 回答