python - 如何设置由 python (rpy2) 执行的 R 代码的时间限制？

Question

我想在 2 秒后停止执行从 python (rpy2) 调用的 R 函数。这是python代码：

signal.signal(signal.SIGALRM, handler)
signal.alarm(2) # set timeout to 2 seconds

# run R code
result = robjects.r('''
      Sys.sleep(10) 
      return("hello")
   ''')

signal.alarm(0) # disable alarm

它不起作用。我必须等待 10 秒等待信号处理程序。

Answer 1

The evaluation of R code does not release the Python GIL. The only way to get a Python script to monitor the execution time of R code is to have two processes.

You could check the unit test for rpy2 "testInterruptR()", although there are much more elegant ways to implement that in an application. There a SIGINT is sent to an R process running an infinite loop.

Answer 2

尝试设置您的警报，然后将您希望超时的操作放在 try catch 块内。警报应该抛出一个可捕获的异常。希望这是有道理的，无论如何它对我有用。