1

我的 sql 语句不适用于 Zend，它抱怨 Count(*) 字段......我做错了什么？

// get open/closed
$stmt = $db->query('SELECT status, count(*) as total FROM reported_issues WHERE date_reported >= '.$today.' AND status IN (0,1) GROUP BY status');
while ($row = $stmt->fetch())
{
    switch ($row['status'])
    {
        case 0:
            $totalIssuesToday = $row['total'];
            break;

        case 1:
            $totalIssuesClosedToday = $row['total'];
            break;
    }
}

和错误...

Fatal error: Uncaught exception 'Zend_Db_Statement_Exception' with message
'SQLSTATE[42S22]: Column not found: 1054 Unknown column 'Y' in 'where clause''
in C:\xampp\htdocs\dating\trunk\library\Zend\Db\Statement\Pdo.php:238

Stack trace:
#0 C:\xampp\htdocs\dating\trunk\library\Zend\Db\Statement.php(283): Zend_Db_Statement_Pdo->_execute(Array)
#1 C:\xampp\htdocs\dating\trunk\library\Zend\Db\Adapter\Abstract.php(484): Zend_Db_Statement->execute(Array)
#2 C:\xampp\htdocs\dating\trunk\library\Zend\Db\Adapter\Pdo\Abstract.php(235): Zend_Db_Adapter_Abstract->query('SELECT status, ...', Array)
#3 C:\xampp\htdocs\dating\trunk\html\siteadmin.php(59): Zend_Db_Adapter_Pdo_Abstract->query('SELECT status, ...')
#4 {main} thrown in C:\xampp\htdocs\dating\trunk\library\Zend\Db\Statement\Pdo.php on line 238
4

3 回答 3

6

除了其他人已经注意到您在 $today 中的价值之外，您确实应该在查询中使用绑定参数

<?php

$stmt = $db->query(
    "SELECT status, count(*) as total
       FROM reported_issues
      WHERE date_reported >= ?
        AND status IN (0,1)
      GROUP BY status"
    ,array( $today )
);
于 2009-06-05T15:27:52.903 回答
3

投诉实际上是关于WHERE-- 看起来你的$today变量不包含你认为它应该包含的内容。具体来说，因为它说：

'SQLSTATE[42S22]: Column not found: 1054 Unknown column 'Y' in 'where clause''

看来您的变量包含一个Y不应该存在的变量。count似乎与该问题无关。

于 2009-06-05T15:21:56.893 回答
3

我猜您的 $today 变量已损坏。更改第一行（用于测试）

从

$stmt = $db->query('SELECT status, count(*) as total FROM reported_issues WHERE date_reported >= '.$today.' AND status IN (0,1) GROUP BY status');

到：

$sql='SELECT status, count(*) as total FROM reported_issues WHERE date_reported >= '.$today.' AND status IN (0,1) GROUP BY status';
try{
   $stmt = $db->query($sql);
} catch (Exception $e) {
   echo $sql."\n";
   throw $e;
}

然后你可以看到它试图执行的原始 SQL。

于 2009-06-05T15:23:56.420 回答