php - 按索引合并两个数组

Question

好吧，如果觉得这应该很简单，并通过类似array_merge()or的函数来完成array_merge_recursive，但我不太明白。我有两个简单的数组，其结构类似于下面的（简化）示例。我只是想根据它们的索引将它们合并到一个数组中。

$数组1：

Array ( 
  [0] => Array ( 
        [ID] => 201 
        [latLng] => 45.5234515, -122.6762071 
  )  
  [1] => Array ( 
        [ID] => 199 
        [latLng] => 37.7931446, -122.39466520000002 
  )
)

等等……</p>

$array2 ：

Array ( 
  [0] => Array ( 
        [distance] => 1000 
        [time] => 10 
  )  
  [1] => Array ( 
        [distance] => 1500 
        [time] => 15 
  )
)

$desiredResult :

Array ( 
  [0] => Array ( 
        [ID] => 201 
        [latLng] => 45.5234515, -122.6762071 
        [distance] => 1000 
        [time] => 10 
 )  
  [1] => Array ( 
        [ID] => 199 
        [latLng] => 37.7931446, -122.39466520000002 
        [distance] => 1500 
        [time] => 15 
 )
)

当我尝试使用合并函数合并这些时，我只能得到这个：

$unDesiredResult:

Array ( 
  [0] => Array ( 
        [ID] => 201 
        [latLng] => 45.5234515, -122.6762071 
  )  
  [1] => Array ( 
        [ID] => 199 
        [latLng] => 37.7931446, -122.39466520000002 
  )
  [2] => Array ( 
        [distance] => 1000 
        [time] => 10 
  )  
  [3] => Array ( 
        [distance] => 1500 
        [time] => 15 
  )
)

我是否需要循环将第二组推入第一组，或者这可以通过现有功能完成吗？

score 13 · Accepted Answer

我认为没有功能可以为您执行此操作，您将不得不循环。

$result = array();
foreach($array1 as $key=>$val){ // Loop though one array
    $val2 = $array2[$key]; // Get the values from the other array
    $result[$key] = $val + $val2; // combine 'em
}

或者您可以将数据推送到 $array1，因此您需要创建第三个数组：

foreach($array1 as $key=>&$val){ // Loop though one array
    $val2 = $array2[$key]; // Get the values from the other array
    $val += $val2; // combine 'em
}

score 3 · Accepted Answer

您需要使用循环。尝试创建一个函数：

function addArray( array &$output, array $input ) {
    foreach( $input as $key => $value ) {
        if( is_array( $value ) ) {
            if( !isset( $output[$key] ) )
                $output[$key] = array( );
            addArray( $output[$key], $value );
        } else {
            $output[$key] = $value;
        }
    }
}

然后：

$combinedArray = array( );
addArray( $combinedArray, $array1 );
addArray( $combinedArray, $array2 );

score 1 · Accepted Answer

示例数组必须合并：

 [location_coordinates] => Array
                                (
                                    [0] => 36.037939100000,-78.905221600000
                                    [1] => 36.004398400000,-78.936084600000
                                )

                            [tm_field_reference_locations$field_location_address$city] => Array
                                (
                                    [0] => Durham
                                    [1] => Durham
                                )

                            [doctor_city] => Array
                                (
                                    [0] => Durham
                                    [1] => Durham
                                )

                            [tm_field_reference_locations$field_location_address$street] => Array
                                (
                                    [0] => 407 Crutchfield Street
                                    [1] => 40 Duke Medicine Circle
                                )

                            [tm_field_reference_locations$field_office_phone] => Array
                                (
                                    [0] => 919-479-4120
                                    [1] => 919-613-0444
                                )

                            [sm_field_reference_locations$title] => Array
                                (
                                    [0] => Duke Regional Hospital Spine and Neurosciences
                                    [1] => Duke Spine Center
                                )

当你像下面这样循环时：

        $address= array();
for($n=0; $n<sizeof($kolDetails['location_coordinates']); $n++){
    $address[$n]['org_institution_id']=$kolDetails['sm_field_reference_locations$title'][$n];
    $address[$n]['longitude']=$kolDetails['location_coordinates'][$n];
    $address[$n]['City']=$kolDetails['doctor_city'][$n];
    $address[$n]['address1']=$kolDetails['tm_field_reference_locations$field_location_address$street'][$n];                 
    $address[$n]['phone_number']=$kolDetails['tm_field_reference_locations$field_office_phone'][$n];        
     }
     $kolextra['adress']=$address;
     pr($kolextra['adress']);
     $address = array();

score 0 · Accepted Answer

我会在一段时间内稍微改变一下。这假设您的值始终被锁定，并且 array1 的第一条记录始终与 array2 的第一条记录相对应：

$i = 0; // sets counter
$end = count($array1); // finds record number
while($i <= $end){ //for each record in the array
    $array1[$i]['distance'] = $array2[$i]['distance'];  //match up array values
    $array1[$i]['time'] = $array2[$i]['time'];  //match up array values
    $i++; //iterate
}

祝你好运！

php - 按索引合并两个数组

4 回答 4

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