所以...
我正在创建一个插件。
我有一个名为 Basics 的主类
我在全球范围内创建的基础知识:
static Timer enterdungeon = new Timer();
static Timer finddungeon = new Timer();
static Timer lootdungeon = new Timer();
我也有一个名为任务的类
enterdungeon 计时器是一个固定的时间段,使用时似乎可以按预期工作。你的lootdungeon计时器也是如此。
如果触发了基础事件,则可以中断 finddungeon 计时器。
该事件确实触发了该事件的第一行是: finddungeon.cancel();
在它启动lootdungeon计时器之后。
问题是 finddungeon 计时器没有取消,它继续运行,下面是任务类:
import java.util.TimerTask;
import me.boduzapho.Basics.DoWarp.Returner;
import org.bukkit.entity.Player;
public class task extends TimerTask
{
private final Player _player;
private final int ticks;
private int cnt = 0;
private final int _sec;
private final String _message;
public task(Player player, int sec, String message)
{
this._player = player;
this._sec = sec;
this._message = message;
this.ticks = sec;
}
private void timetoloot(Player p)
{
p.sendMessage("SUCCESS! Nice Job, Enjoy the loot!");
Returner loc1 = DoWarp.getwarp("launch", Basics.warps, Basics.wx,Basics.wy, Basics.wz, p);
DoWarp.warpme(loc1.x, loc1.y, loc1.z, p, false, Basics.plugin);
}
private void failedwhiteblock(Player p)
{
p.sendMessage("FAIL! You did not find the white block. Sending you back. TRY AGAIN!");
Returner loc1 = DoWarp.getwarp("launch", Basics.warps, Basics.wx, Basics.wy, Basics.wz, p);
DoWarp.warpme(loc1.x, loc1.y, loc1.z, p, false, Basics.plugin);
}
private void enterdungeon(Player p)
{
Basics.Stage.setLine(3, "Off you Go!");
Basics.Stage.update();
Basics.Stage.setLine(0, "");
Basics.Stage.setLine(1, "");
Basics.Stage.setLine(2, "");
Basics.Stage.setLine(3, "");
Basics.Stage.update();
Basics.cDoClear(p);
Basics.cDoSpawners(p);
Basics.cDoRed(p);
Returner loc1 = DoWarp.getwarp("dstart", Basics.warps, Basics.wx, Basics.wy, Basics.wz, p);
DoWarp.warpme(loc1.x, loc1.y, loc1.z, p, false, Basics.plugin);
Basics.DungeonPlayer = p;
p.sendMessage("Welcome to the Dungeon, you have 1 minuite to locate and click the white block.");
p.sendMessage("If you fail you will be returned to spawn. If you find it the treasures will be revieled");
p.sendMessage("and the monsters banished for 1 min so you can loot the chests! After which you will");
p.sendMessage("Be warped back to spawn with your Loot!");
Basics.finddungeon.schedule(new task(_player, 30, "Time left to find the WHITE block :"), 0, 1000);
Basics.enterdungeon.cancel();
}
@Override
public void run()
{
while (cnt < ticks)
{
try
{
Thread.sleep(1 * 1000);
_player.sendMessage(_message + " " + Integer.toString(_sec - cnt));
++cnt;
}
catch (InterruptedException e)
{
// TODO Auto-generated catch block
e.printStackTrace();
}
}
_player.sendMessage("Done!");
if (_message == "Time left:")
{
enterdungeon(_player);
}
if (_message == "Time left to find the WHITE block :")
{
failedwhiteblock(_player);
}
if (_message == "Time left to LOOT:")
{
timetoloot(_player);
}
//
return;
}
}
这是在 Basics(主类)中调用的函数,它应该取消 finddungeon 计时器。
// white block in dungeon
if (DungeonPlayer == player)
{
if ((block != null) && (block.getType() == Material.WOOL))
{
player.sendMessage("Canceling finddungeon from Basics");
finddungeon.cancel();
cDoClear(player);
cDoChests(player);
player.sendMessage("Congradulations! Time to Loot your rewards for finding the White Block!");
Timer lootdungeon = new Timer();
lootdungeon.schedule(new task(player, 10, "Time left to LOOT:"), 0, 1000);
return;
// ***
}
}
任何人都可以对此有所了解吗?