7

我编写了一个转换器类，它接受一个 HttpServletRequest 并将其转换为另一种类型，该类型包含一个指向来自 servlet 请求的 InputStream 的指针。（这个想法是从请求处理中抽象传入传输协议，所以我也可以从 FTP 编写一个类似的转换器，例如。）

现在我正在尝试为此编写一个单元测试，但我遇到了问题。我已经设法找出正确的样板来创建有效的多部分 HTTP 请求（使用 Spring 类 MockMultipartHttpServletRequest 和 MockMultipartFile），但现在我在我的类的initialize()方法中得到了 NullPointerException。UploadRequest我猜问题是 MockMultipartHttpServletRequest 内部的流以某种方式没有被正确初始化，但我不知道我应该做些什么不同的事情。

任何建议将不胜感激！

这是堆栈跟踪：

java.lang.NullPointerException
    at org.apache.commons.fileupload.MultipartStream$ItemInputStream.makeAvailable(MultipartStream.java:976)
    at org.apache.commons.fileupload.MultipartStream$ItemInputStream.read(MultipartStream.java:886)
    at java.io.InputStream.read(InputStream.java:82)
    at org.apache.commons.fileupload.util.Streams.copy(Streams.java:96)
    at org.apache.commons.fileupload.util.Streams.copy(Streams.java:66)
    at org.apache.commons.fileupload.MultipartStream.readBodyData(MultipartStream.java:592)
    at org.apache.commons.fileupload.MultipartStream.discardBodyData(MultipartStream.java:618)
    at org.apache.commons.fileupload.MultipartStream.skipPreamble(MultipartStream.java:637)
    at org.apache.commons.fileupload.FileUploadBase$FileItemIteratorImpl.findNextItem(FileUploadBase.java:984)
    at org.apache.commons.fileupload.FileUploadBase$FileItemIteratorImpl.<init>(FileUploadBase.java:965)
    at org.apache.commons.fileupload.FileUploadBase.getItemIterator(FileUploadBase.java:331)
    at org.apache.commons.fileupload.servlet.ServletFileUpload.getItemIterator(ServletFileUpload.java:148)
    at com.ooyala.UploadRequest.initialize(UploadRequest.java:51)
    at com.ooyala.UploadRequestTest.testCreateFromServletRequest(UploadRequestTest.java:57)

这是我的变压器类的缩写版本：

public class UploadRequest {
  private Map<String, String> params;
  private InputStream strIn;
  private Logger Log = Logger.getLogger(UploadRequest.class.getName());

  public UploadRequest()
  {
    params = new HashMap<String, String>();
  }

  public void initialize(HttpServletRequest sRequest, 
                         ServletFileUpload upload)
    throws IOException, FileUploadException
  {
    Enumeration<String> paramNames = sRequest.getParameterNames();
    while (paramNames.hasMoreElements()) {
      String pName = paramNames.nextElement();
      params.put(pName, sRequest.getParameter(pName));
    }
    params.put("request_uri", sRequest.getRequestURI());

    FileItemIterator iter = upload.getItemIterator(sRequest);
    while (iter.hasNext()) {
      FileItemStream item = iter.next();
      try {
        if (!item.isFormField()) {
          // Skip form fields
          params.put("original_file_name", item.getName());
          strIn = item.openStream();
        } 
      } catch (IOException ex) {
        Log.severe("File uploading exception: " + ex.getMessage());
        throw ex;
      }
    }
  }

这是单元测试：

import org.springframework.mock.web.MockMultipartHttpServletRequest;
import org.springframework.mock.web.MockMultipartFile;
import org.apache.commons.fileupload.servlet.ServletFileUpload;
// etc.... other imports

@RunWith(JMock.class)
public class UploadRequestTest {
  private UploadRequest upRequest;

  @Before
    public void setUp()
    {
      context.setImposteriser(ClassImposteriser.INSTANCE);
      upRequest = new UploadRequest();
    }

  @Test
    public void testCreateFromServletRequest()
      throws IOException, FileUploadException
    {
      String text_contents = "hello world";

      MockMultipartHttpServletRequest sRequest = 
        new MockMultipartHttpServletRequest();
      sRequest.setMethod("POST");
      String boundary = generateBoundary();
      String contentType = "multipart/form-data; boundary="+boundary;
      sRequest.setContentType(contentType);
      sRequest.setRequestURI("/foo");
      sRequest.addParameter("test_param","test_value");
      sRequest.addFile(
        new MockMultipartFile("file1","test_upload.txt","text/plain",
          text_contents.getBytes()));

      ServletFileUpload upload = new ServletFileUpload();
      assertTrue(upload.isMultipartContent(sRequest));

      upRequest.initialize(sRequest, upload);
    }
}
4

3 回答 3

2

我有同样的问题，我用谷歌搜索但没有答案。我从库中插入源代码，您需要发送内容，无论如何。库可能需要在 skip 方法中检查它是否为 null

MockMultipartHttpServletRequest request
request.setContent("whatever".getBytes());

在这里发布给其他人

于 2012-04-04T22:04:28.837 回答
1
  1. 添加边界条件

  2. 生成内容如下

    MockMultipartHttpServletRequest request = 
    this.generateMockMultiPartHttpServletRequest(true);
MockMultipartFile mockMultipartFile = null;
try {
    request.setContentType("multipart/form-data; boundary=-----1234");
    request.setCharacterEncoding("text/plain");
    String endline = "\r\n";
    String bondary = "-----1234";
    String textFile = this.encodeTextFile("-----1234", "\r\n", "file","test.csv",
        "text/UTF-8", FileUtils.readFileToString((new File(csvFilePath)), "UTF-8"));
    StringBuilder content = new StringBuilder(textFile.toString());
    content.append(endline);
    content.append(endline);
    content.append(endline);
    content.append("--");
    content.append(bondary);
    content.append("--");
    content.append(endline);
    request.setContent(content.toString().getBytes());
    request.setMethod("POST");
    mockMultipartFile = new MockMultipartFile("file",
    FileUtils.readFileToByteArray(new File(csvFilePath)));
} catch (Exception e1) {
    e1.printStackTrace();
}
 request.addFile(mockMultipartFile);

文本编码函数

    private String encodeTextFile(String bondary, String endline, String name, 
        String filename, String contentType, String content) {

        final StringBuilder sb = new StringBuilder(64);
        sb.append(endline);
        sb.append("--");
        sb.append(bondary);
        sb.append(endline);
        sb.append("Content-Disposition: form-data; name=\"");
        sb.append(name);
        sb.append("\"; filename=\"");
        sb.append(filename);
        sb.append("\"");
        sb.append(endline);
        sb.append("Content-Type: ");
        sb.append(contentType);
        sb.append(endline);
        sb.append(endline);
        sb.append(content);
        return sb.toString();
    }
于 2013-02-08T09:33:51.370 回答
1

我遇到了同样的问题，经过大量搜索后，我得到了这篇文章，其中我回答了解决我的问题的代码。

Shriprasad 的解决方案适用于文本文件。但是我对二进制文件有一些问题。

https://stackoverflow.com/a/30541653/2762092

于 2015-05-30T03:00:28.797 回答