我有两张桌子,“po”和“receive”
CREATE TABLE `po` (
`PO_ID` bigint(20) NOT NULL,
`SERVICE_TYPE` bit(1) DEFAULT NULL,
`ENTRY_DATE` date NOT NULL,
`RECEIPT_DATE` date DEFAULT NULL,
`TURNOVER` date DEFAULT NULL,
`MOBILIZATION` date DEFAULT NULL,
`SITE_NAME` varchar(255) NOT NULL,
`SITE_CODE` varchar(45) DEFAULT NULL,
`SITE_TIN` varchar(45) DEFAULT NULL,
`SITE_ADDRESS` varchar(255) NOT NULL,
`COST` decimal(11,2) NOT NULL,
`XML` text,
PRIMARY KEY (`PO_ID`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8$$
CREATE TABLE `receive` (
`RECEIPT_ID` varchar(100) NOT NULL,
`RECEIPT_DATE` date NOT NULL,
`PO_NUMBER` bigint(20) NOT NULL,
`SUPPLIER_ID` int(11) NOT NULL,
PRIMARY KEY (`RECEIPT_ID`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8$$
我试图通过在表'receive'上定义外键'fk_po'来连接两个表
ALTER TABLE `fourthwave`.`receive`
ADD CONSTRAINT `fk_po`
FOREIGN KEY (`PO_NUMBER` )
REFERENCES `fourthwave`.`po` (`PO_ID` )
ON DELETE SET NULL
ON UPDATE SET NULL
, ADD INDEX `fk_po` (`PO_NUMBER` ASC)
但是,上面的 alter 查询会引发错误:
Error Code: 1005. Can't create table 'fourthwave.#sql-aec_11' (errno:150)
我收到此错误是因为两个表上的字段名称“PO_ID”和“PO_NUMBER”不同吗?