java - 如何在 StringTokenizer 中使用正则表达式

Question

StringTokenizer st = new StringTokenizer(remaining, "\t\n\r\"'>#");

String strLink = st.nextToken();

剩余字符串的输入可以是以下之一：

1. "http://somegreatsite.com">Link Name</a>is a link to another nifty site<H1>This is a Header</H1><H2>This is a Medium Header</H2>Send me mail at <a href="mailto:support@yourcompany.com">support@yourcompany.com</a>.<P> This is a new paragraph!<P> <B>This is a new paragraph!</B><BR> <B><I>This is a new sentence without a paragraph break, in bold italics.</I></B><HR></BODY></HTML>

2. "mailto:support@yourcompany.com">support@yourcompany.com</a>.<P> This is a new paragraph!<P> <B>This is a new paragraph!</B><BR> <B><I>This is a new sentence without a paragraph break, in bold italics.</I></B><HR></BODY></HTML>

我知道构造函数会使用正则表达式StringTokenizer将字符串拆分为标记。*remaining*但我无法理解这里使用的正则表达式。

将strLink根据字符串中的值具有以下值*remaining*：

1. http://somegreatsite.com
2.mailto:support@yourcompany.com

请帮助我理解上面代码中使用的正则表达式。

Answer 1

这些字符\t\n\r\"'>#不是正则表达式，而是分隔符。例如，您可以在Pattern类中看到特殊字符的含义。

\t - The tab character
\n - The newline (line feed) character
\r - The carriage-return character
\" - this is just a double quote
', >, # - other symbols