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上周我决定尝试使用 Google 购物 API，但我不知道如何解析 JCON 对象。

经过在这里的大量搜索，我能够获得一个项目的产品信息！但是，我不能缩小到产品中的一个字符串。因此，例如，我只想获得产品的标题。

我有以下内容：

json字符串：

{
 "kind": "shopping#products",
 "etag": "\"GKsxsRlaBDslDpMe-MT1O7wqUDE/dMvQ5Pu2C806fWZJbNJ0GjdesJs\"",
 "id": "tag:google.com,2010:shopping/products",
 "selfLink": "https://www.googleapis.com/shopping/search/v1/public/products?country=US&restrictBy=gtin:051500240908&startIndex=1&maxResults=25",
 "totalItems": 3,
 "startIndex": 1,
 "itemsPerPage": 25,
 "currentItemCount": 3,
 "items": [
  {
   "kind": "shopping#product",
   "id": "tag:google.com,2010:shopping/products/7585088/9884865157760252836",
   "selfLink": "https://www.googleapis.com/shopping/search/v1/public/products/7585088/gid/9884865157760252836",
   "product": {
    "googleId": "9884865157760252836",
    "author": {
     "name": "Southeastern Delivery",
     "accountId": "7585088"
    },
    "creationTime": "2011-07-25T00:15:58.000Z",
    "modificationTime": "2012-02-11T09:29:00.000Z",
    "country": "US",
    "language": "en",
    "title": "Jif Peanut Butter, Creamy",
    "description": "Jif Creamy Peanut Butter. Fresh Roasted Peanut Taste. Look for the flavor seal. Contains no preservatives. No refrigeration required.",
    "link": "http://www.southeasterndelivery.com/Jif_Peanut_Butter_00051500240908/",
    "brand": "Jif Peanut Butter",
    "condition": "new",
    "gtin": "00051500240908",
    "gtins": [
     "00051500240908"
    ],
    "inventories": [
     {
      "channel": "online",
      "availability": "inStock",
      "price": 15.64,
      "shipping": 1.56,
      "currency": "USD"
     }
    ],
    "images": [
     {
      "link": "http://www.southeasterndelivery.com/images/ProductImages/00051500240908.jpg"
     }
    ]
   }
  },
 ],
 "requestId": "0CLGzkcKVo64CFRDd5wod4mMAAA"
 }

我的 android 应用程序中有以下代码来解析它：

try {

    JSONObject jsonObject = new JSONObject(jsonString);
    JSONArray itemsArray = jsonObject.getJSONArray("items");
    JSONObject productObject = itemsArray.getJSONObject(0);
    //String productTitle = productObject.getString("title");
    //tv.setText(productTitle);
    tv.setText(productObject.toString());
} catch (JSONException e) {
    // TODO Auto-generated catch block
    tv.setText("JSONOBJECT Error: " + e);
    e.printStackTrace();
}
setContentView(tv);

我的 Android 应用程序上的 TextView 现在将显示（显然没有缩进，我这样做是为了便于阅读）：

   "product": {
    "googleId": "9884865157760252836",
    "author": {
     "name": "Southeastern Delivery",
     "accountId": "7585088"
    },
    "creationTime": "2011-07-25T00:15:58.000Z",
    "modificationTime": "2012-02-11T09:29:00.000Z",
    "country": "US",
    "language": "en",
    "title": "Jif Peanut Butter, Creamy",
    "description": "Jif Creamy Peanut Butter. Fresh Roasted Peanut Taste. Look for the flavor seal. Contains no preservatives. No refrigeration required.",
    "link": "http://www.southeasterndelivery.com/Jif_Peanut_Butter_00051500240908/",
    "brand": "Jif Peanut Butter",
    "condition": "new",
    "gtin": "00051500240908",
    "gtins": [
     "00051500240908"
    ],
    "inventories": [
     {
      "channel": "online",
      "availability": "inStock",
      "price": 15.64,
      "shipping": 1.56,
      "currency": "USD"
     }
    ],
    "images": [
     {
      "link": "http://www.southeasterndelivery.com/images/ProductImages/00051500240908.jpg"
     }
    ]
   }

现在，如果您注意到我的 Java 代码中有两行注释掉了。如果我取消注释这些行，然后注释该行：

tv.setText(productObject.toString());

tv 设置为此错误：“JSONOBJECT 错误：org.json.JSONEception：标题没有值”。我不确定为什么这是真的，因为很明显它们是 productObject 中的标题。

任何帮助都会很棒！

4

2 回答 2

2

我在我的项目中使用json-smart。它非常小而且非常快。要将 JSON 从 Sting 转换为实际对象，请使用JSONObjet json = (JSONObject)JSONValue.parse(rawString);

当您拥有 JSONObject 时，您将其视为 Map。所以String title = (String) json.get("title")

于 2012-02-21T19:17:06.837 回答
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您的代码中缺少一定级别的信息。JSON 数组包含项目，其中包含具有标题的产品。

您的代码应如下所示：

JSONObject jsonObject = new JSONObject(jsonString); 
JSONArray itemsArray = jsonObject.getJSONArray("items"); 
JSONObject itemObject = itemsArray.getJSONObject(0); 
JSONObject productObject = itemObject.getJSONObject("product");
String productTitle = productObject.getString("title");
于 2012-02-21T20:18:07.843 回答