1

嗨，我是 vba 的新手，我可能不太了解它，但我无法解释为什么在代码应该更改单元格的背景颜色时出现“运行时错误 9：下标超出范围”错误给另一个

 Sub CompareWorksheets(ws1 As Worksheet, ws2 As Worksheet)
    Dim r As Long, c As Integer
    Dim lr1 As Long, lr2 As Long, lc1 As Integer, lc2 As Integer
    Dim maxR As Long, maxC As Integer, cf1 As String, cf2 As String
    Dim DiffCount As Long
    Application.ScreenUpdating = False
    With ws1.UsedRange
        lr1 = .Rows.Count
        lc1 = .Columns.Count
    End With
    With ws2.UsedRange
        lr2 = .Rows.Count
        lc2 = .Columns.Count
    End With
    maxR = lr1
    maxC = lc1
    If maxR < lr2 Then maxR = lr2
    If maxC < lc2 Then maxC = lc2
    DiffCount = 0
    For c = 1 To maxC
        For r = 1 To maxR
            cf1 = ""
            cf2 = ""
            On Error Resume Next
            cf1 = ws1.Cells(r, c).FormulaLocal
            cf2 = ws2.Cells(r, c).FormulaLocal
            On Error GoTo 0
            If cf1 <> cf2 Then
                DiffCount = DiffCount + 1
                ws1.Cells(r, c).Activate
                ws1.Cells(r, c).Select
 =============> ws1.Cells(r, c).Interior.ColorIndex = RGB(200, 20, 20) <============
                End If
            Next r
        Next c
        Application.ScreenUpdating = True
    End Sub
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2 回答 2

5

Cell.Interior.ColorIndex不是RGB值，而是枚举值。
可能的值为：

  • xlColorIndexAutomatic 这意味着自动颜色
  • xlColorIndexNone 这意味着没有颜色

这就是您无法成功将其设置为RGB值的原因。

要将背景颜色设置为RGB颜色，请改用该Interior.Color属性。

于 2012-02-20T21:27:29.830 回答
0

我发现在 RGB(#,#,#) 中使用带有&H标签的Interior.Color也可以。

例子：

RGB = 192 0 0 -------- 十六进制 = #C00000 ------ RGB(&HC0, &H0, &H0)
RGB = 84 130 53 ---- 十六进制 = #548235 ------ RGB (&H54, &H82, &H35)

Range("C1").Interior.Color = RGB(&HC0, &H0, &H0)
Range("C1").Interior.Color = RGB(&H54, &H82, &H35)

单元格(1, 3).Interior.Color = RGB(&HC0, &H0, &H0)
单元格(1, 3).Interior.Color = RGB(&H54, &H82, &H35)

于 2021-03-05T17:41:52.270 回答