我正在扫描一个带有几个分隔符的数独板的文本文件。这就是示例输入的样子。
1 - - | 4 5 6 | - - -
5 7 - | 1 3 b | 6 2 4
4 9 6 | 8 7 2 | 1 5 3
======+=======+======
9 - - | - - - | 4 6 -
6 4 1 | 2 9 7 | 8 3 -
3 8 7 | 5 6 4 | 2 9 -
======+=======+======
7 - - | - - - | 5 4 8
8 r 4 | 9 1 5 | 3 7 2
2 3 5 | 7 4 $ | 9 1 6
哪里有“|” 作为边界和 =====+====+==== 作为分隔符。我做了这个代码来忽略 | 和 ====+===+=== 但它跳过了那部分代码并将它们声明为无效字符并在那里添加 0
public static int [][] createBoard(Scanner input){
int[][] nSudokuBoard = new int[9][9];
for (rows = 0; rows < 9; rows++){
for (columns = 0; columns < 9; columns++){
if(input.hasNext()){
if(input.hasNextInt()){
int number = input.nextInt();
nSudokuBoard[rows][columns] = number;
}//end if int
else if(input.hasNext("-")){
input.next();
nSudokuBoard[rows][columns] = 0;
System.out.print("Hyphen Found \n");
}//end if hyphen
else if(input.hasNext("|")){
System.out.print("border found \n");
input.next();
}// end if border
else if(input.hasNext("======+=======+======")){
System.out.print("equal row found \n");
input.next();
}// end if equal row
else {
System.out.print("Invalid character detected at... \n Row: " + rows +" Column: " + columns +"\n");
System.out.print("Invalid character(s) replaced with a '0'. \n" );
input.next();
}//end else
}//end reading file
}//end column for loop
}//end row for looop
return nSudokuBoard;
}//end of createBoard
我和导师讨论过，但我不记得他关于如何解决这个问题的建议。