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SocialEngine4：如何使用 sql 查询获取用户的性别？

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4 回答 4

2 
$subject = Engine_Api::_()->core()->getSubject(); //Get user

$fields = $subject->fields()->getFieldsValuesByAlias();
$gender = $fields['gender'];

$this->view->gender = $gender;
于 2013-04-15T23:55:51.527 回答
1 
$viewer = Engine_Api::_()->user()->getViewer();
$fields = Engine_Api::_()->fields()->getFieldsValuesByAlias($viewer);
echo $fields['gender'];
于 2012-08-30T09:58:03.813 回答
1

使用下面列出的代码：

<?php
$currentUserID=Engine_Api::_()->user()->getViewer()->getIdentity();
$sSqlInviter="select gender from engine4_user_fields_search where item_id=".$currentUserID;
$dbInviterSqli=Zend_Db_Table_Abstract::getDefaultAdapter();
$stmtInviter=$dbInviterSqli->query($sSqlInviter);
$rowInviter=$stmtInviter->fetch();
$gender=$rowInviter['gender'];
if($gender==2) 
  echo "<b> Male</b>";
else
  echo "<b> Female</b>";
?>
于 2012-05-25T08:21:56.003 回答
0

您是否使用默认配置文件问题？然后：

From engine4_ser_fields_option

有特定字段的选项 id。

于 2012-02-27T05:55:48.157 回答