5

我发现了很多关于四舍五入“向下”时间值的帖子（例如https://stackoverflow.com/a/6667041/468823），但我还有另一个问题：我想四舍五入到较高的分钟而不是较低的分钟，如何我可不可以做？

我的代码：

SELECT

 PA.ORE AS TOT_HOURS,  
 CAST(CAST(PA.ORA_INIZIO AS DATETIME) AS TIME) AS BEGIN_TIME,
 CAST(dateadd(minute, datediff(minute, 0, (CAST(PA.ORA_INIZIO AS DATETIME))), 0) AS TIME) AS BEGIN_TIME_ROUNDED


FROM PRG_ATTIVITA PA INNER JOIN PRG_TIPI_ATTIVITA PTA ON  PA.ID_TIPO_ATTIVITA = PTA.ID_TIPO_ATTIVITA
                     INNER JOIN PER_ANAGRAFICA PAN ON PA.ID_DIPENDENTE = PAN.ID_DIPENDENTE
WHERE PA.ID_PROGETTO = 1431 and pta.DESCR_TIPO_ATTIVITA like 'F-%remoto%' and ID_ATTIVITA = 41772 

ORDER BY  PA.DATA_ATTIVITA

我的结果如下：

    TOT_HOURS   BEGIN_TIME          BEGIN_TIME_ROUNDED
    1.50        15:59:59.9970000    15:59:00.0000000

我想要 BEGIN_TIME_ROUNDED = 16:00:00.0000000

注意： 1. 我必须转换我的数据 { CAST(PA.ORA_INIZIO AS DATETIME) } 因为在数据库中我有时间数据作为浮点值 2. BEGIN_TIME 是转换后我的时间值的实际值

4

5 回答 5

3 
SELECT  DATEADD(MINUTE, CEILING(DATEDIFF(SECOND, 0, CAST(CAST(PA.ORA_INIZIO AS DATETIME) AS TIME)) / 60.0), DATEDIFF(DAY, 0, PA.ORA_INIZIO)) AS BEGIN_TIME_ROUNDED

编辑

正如评论中指出的那样，这在 0 到 1 秒之间失败。这可以通过简单地将上限的精度从秒更改为毫秒来解决：

SELECT  PA.ORA_INIZIO,
        DATEADD(MINUTE, 
            CEILING(DATEDIFF(MILLISECOND, 0, CAST(PA.ORA_INIZIO AS TIME)) / 60000.0),
            DATEDIFF(DAY, 0, PA.ORA_INIZIO)) AS BEGIN_TIME_ROUNDED
FROM (VALUES 
        (CONVERT(DATETIME, '20211126 15:59:00.997')), 
        (CONVERT(DATETIME, '20211126 15:59:00.004'))
    ) AS PA (ORA_INIZIO);

这使：

ORA_INIZIO BEGIN_TIME_ROUNDED
2021-11-26 15:59:59.997 2021-11-26 16:00:00.000
2021-11-26 15:59:00.003 2021-11-26 16:00:00.000
于 2012-02-14T09:38:48.650 回答
2

只需 CAST 到 smalldatetime 以四舍五入到最接近的分钟

SELECT 
    CAST(CAST('15:59:59.9970000' AS time) AS smalldatetime),
    CAST(CAST('15:59:30.0030000' AS time) AS smalldatetime),
    CAST(CAST('15:59:30.0000000' AS time) AS smalldatetime),
    CAST(CAST('15:59:29.9970000' AS time) AS smalldatetime),
    CAST(CAST('15:59:00.0030000' AS time) AS smalldatetime)

DATEADD/DATEDIFF 用于截断一些时间单位

编辑，误读问题

只需修改您当前的 CAST

CAST(
 DATEADD(minute,
         DATEDIFF(minute, 
                  0, 
                  CAST(PA.ORA_INIZIO AS DATETIME)
                 ) + 1, 
         0
         )
     AS TIME)
于 2012-02-14T09:38:30.503 回答
1

对 SQL Server 不太了解，无法立即回答，但如果没有人提供更实际的方法来做到这一点，那么您可以在四舍五入之前将值添加 1 分钟。或者如果您还需要正确处理整数输入值，则添加 0.999 分钟。

于 2012-02-14T09:34:56.107 回答
0 
DECLARE @ datetime = '2021-11-26 00:00:00.997'
SELECT dateadd(minute, ceiling(cast(@ as float) * 1440),0) ceilingminute
于 2012-02-14T11:41:23.463 回答
0

如果您想将 DATETIME d 舍入到最接近的分钟，您可以这样做：

CONVERT(DATETIME, CONVERT(SMALLDATETIME,
  DATEADD(minute, CASE WHEN d = CONVERT(SMALLDATETIME, d) THEN 0 ELSE 1 END,
  d)))
于 2012-02-14T09:38:42.433 回答