我在 VS2010 中手动执行以下操作。1. 读入 2 个波形文件,比如“1.wav”和“2.wav”。2. 将 2.wav 插入 1.wav 的中间。3. 将结果波形流写入输出文件“out.wav”。
我现在可以使用以下结构成功读取波形文件
typedef struct {
char ChunkID[4]; /* RIFF Header */ //Magic header
unsigned long ChunkSize; /* RIFF Chunk Size */
char Format[4]; /* WAVE Header */
char Subchunk1ID[4]; /* FMT header */
unsigned long Subchunk1Size; /* Size of the fmt chunk */
unsigned short AudioFormat; /* Audio format 1=PCM,6=mulaw,7=alaw, 257=IBM Mu-Law, 258=IBM A-Law, 259=ADPCM */
unsigned short NumChannels; /* Number of channels 1=Mono 2=Sterio */
unsigned long SampleRate; /* Sampling Frequency in Hz */
unsigned long ByteRate; /* bytes per second */
unsigned short BlockAlign; /* 2=16-bit mono, 4=16-bit stereo */
unsigned short BitsPerSample; /* Number of bits per sample */
char Subchunk2ID[4]; /* "data" string */
unsigned long Subchunk2Size; /* Sampled data length */
BYTE Data[18000];
} WavFile;
但是2个wave文件的一些参数不一样。比如1.wav的SampleRate是8000,2.wav的SampleRate是44100,那么out.wav的SampleRate是多少?