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我有一个城市作为行和月份作为列的sql-server代码，有月份的总和，但没有总和city_id，我的意思是我必须在输出中按城市计算所有总和，并将其分组city_id，无论如何这是sql代码：

SELECT 
    SC.CITY_ID,SC.CITY_NAME, DATEPART(MM,I.INVOICE_DATE) AS INVOICE_MONTH,
    JAN=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=1 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
    FEB=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=2 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
    MAR=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=3 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
    APR=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=4 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
    MAY=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=5 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
    JUN=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=6 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
    JUL=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=7 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
    AUG=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=8 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
    SEP=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=9 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
    OCT=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=10 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
    NOV=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=11 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
    DEC=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=12 THEN COALESCE(NETTOTAL,0) ELSE 0 END)
FROM 
    SETUP_CITY SC
    LEFT OUTER JOIN COMPANY C ON C.CITY = SC.CITY_ID
    LEFT OUTER JOIN #DSN2_ALIAS#.INVOICE I ON I.COMPANY_ID = C.COMPANY_ID AND I.INVOICE_CAT IN (50,52,53,531,532,56,58,561,54,55,51,63,48) AND I.PURCHASE_SALES = 1
WHERE SC.COUNTRY_ID=1
GROUP BY SC.CITY_ID,SC.CITY_NAME,I.INVOICE_DATE
ORDER BY SC.CITY_ID,SC.CITY_NAME,I.INVOICE_DATE

和输出：

<cfoutput query="get_top_sales_TOTAL" group="CITY_ID">

如果我不定义 group by city_id，则显示一个城市的多行。如何在 sql 代码中对值进行分组（总结）？这样我就不必在 cfoutput 中使用 group 语句了吗？

这是屏幕截图以使其更清晰，这是定义的屏幕截图group="city_id"

在此处输入图像描述

如果我不定义group="city_id"

在此处输入图像描述

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2 回答 2

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马克对 invoice_month 的看法是正确的，这样做没有意义。您的“正确” sql 应该是

SELECT 
        SC.CITY_ID,SC.CITY_NAME,
        TOTAL=SUM(COALESCE(NETTOTAL,0)),
        JAN=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=1 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
        FEB=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=2 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
        MAR=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=3 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
        APR=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=4 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
        MAY=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=5 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
        JUN=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=6 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
        JUL=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=7 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
        AUG=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=8 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
        SEP=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=9 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
        OCT=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=10 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
        NOV=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=11 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
        DEC=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=12 THEN COALESCE(NETTOTAL,0) ELSE 0 END)
FROM 
        SETUP_CITY SC
            LEFT OUTER JOIN COMPANY C ON C.CITY = SC.CITY_ID
            LEFT OUTER JOIN #DSN2_ALIAS#.INVOICE I ON I.COMPANY_ID = C.COMPANY_ID 
                    AND I.INVOICE_CAT IN (50,52,53,531,532,56,58,561,54,55,51,63,48) 
                    AND I.PURCHASE_SALES = 1
WHERE  SC.COUNTRY_ID=1
GROUP BY SC.CITY_ID, SC.CITY_NAME
ORDER BY SC.CITY_ID,SC.CITY_NAME
于 2012-02-11T16:24:58.230 回答
0

您的问题是 group by 和 order by 中的“invoice_date”将产生多行。尝试这个：

GROUP BY SC.CITY_ID, SC.CITY_NAME, DATEPART(MM,I.INVOICE_DATE)
ORDER BY SC.CITY_ID, SC.CITY_NAME,  INVOICE_MONTH

不能尝试，所以我不能调试它 - 但基本上你的 GROUP 不能有单独的项目来扩展行的唯一性（就像“发票日期”可能会做的那样）。祝你好运！

于 2012-02-11T16:04:02.280 回答