3

我正在尝试使用 jak 导入 mkl 文件，但出现以下错误：

javax.xml.bind.UnmarshalException：意外元素（uri：“http://earth.google.com/kml/2.2”，本地：“kml”）。预期的元素是......然后是一个大列表

还有其他人遇到这个问题吗？

这是代码：

final Kml kml = Kml.unmarshal(new File("../data/Eemskanaal.kml"));
        final Placemark placemark = (Placemark) kml.getFeature();
        Point point = (Point) placemark.getGeometry();
        List<Coordinate> coordinates = point.getCoordinates();
        for (Coordinate coordinate : coordinates) {
            System.out.println(coordinate.getLatitude());
            System.out.println(coordinate.getLongitude());
            System.out.println(coordinate.getAltitude());
        }

这是 kml 文件：

<?xml version="1.0" encoding="UTF-8"?>
<kml xmlns="http://earth.google.com/kml/2.2">
<Document>
  <name>BU00100107 Verspreide huizen Eemskanaal (ten zuiden)</name>
  <description><![CDATA[description]]></description>
  <Placemark>
    <name>BLA!</name>
    <description><![CDATA[]]></description>
    <styleUrl>#style1</styleUrl>
    <Polygon>
      <outerBoundaryIs>
        <LinearRing>
          <tessellate>1</tessellate>
          <coordinates>
            6.941796,53.314914,0.000000
            6.942705,53.310923,0.000000
            6.952713,53.305394,0.000000
            6.954853,53.300262,0.000000
            6.954239,53.296317,0.000000
            6.962271,53.295483,0.000000
            6.995900,53.287338,0.000000
            6.995013,53.285264,0.000000
            6.996842,53.281429,0.000000
            6.991748,53.278255,0.000000
            6.990729,53.275234,0.000000
            6.988361,53.274477,0.000000
            6.990120,53.271780,0.000000
            6.984540,53.272709,0.000000
            6.984543,53.274393,0.000000
            6.980317,53.274404,0.000000
            6.975829,53.272503,0.000000
            6.974816,53.271125,0.000000
            6.963342,53.271937,0.000000
            6.955082,53.265909,0.000000
            6.945183,53.269634,0.000000
            6.940684,53.273351,0.000000
            6.935942,53.273875,0.000000
            6.934392,53.276351,0.000000
            6.929104,53.272181,0.000000
            6.909544,53.265952,0.000000
            6.908803,53.269015,0.000000
            6.909151,53.278897,0.000000
            6.888166,53.279161,0.000000
            6.887788,53.279639,0.000000
            6.886750,53.280950,0.000000
            6.886729,53.280977,0.000000
            6.888260,53.281856,0.000000
            6.895912,53.286254,0.000000
            6.892976,53.288089,0.000000
            6.891571,53.290803,0.000000
            6.887323,53.298046,0.000000
            6.887729,53.309725,0.000000
            6.887583,53.309816,0.000000
            6.888683,53.311891,0.000000
            6.893966,53.313119,0.000000
            6.924732,53.311548,0.000000
            6.929655,53.312392,0.000000
            6.934810,53.315353,0.000000
            6.941796,53.314914,0.000000
          </coordinates>
        </LinearRing>
      </outerBoundaryIs>
    </Polygon>
    <Polygon>
      <outerBoundaryIs>
        <LinearRing>
          <tessellate>1</tessellate>
          <coordinates>
            6.905549,53.283453,0.000000
            6.908790,53.282516,0.000000
            6.912146,53.283305,0.000000
            6.916480,53.287575,0.000000
            6.916764,53.288072,0.000000
            6.915251,53.288369,0.000000
            6.915097,53.290097,0.000000
            6.912526,53.292361,0.000000
            6.908052,53.290971,0.000000
            6.905569,53.288875,0.000000
            6.905549,53.283453,0.000000
          </coordinates>
        </LinearRing>
      </outerBoundaryIs>
    </Polygon>
</Placemark>
</Document>
</kml>

也欢迎任何其他解决方案

4

3 回答 3

2

这是我快速而肮脏的方式:)

public static Kml getKml(InputStream is) throws Exception {
    String str = IOUtils.toString( is );
    IOUtils.closeQuietly( is );
    str = StringUtils.replace( str, "xmlns=\"http://earth.google.com/kml/2.2\"", "xmlns=\"http://www.opengis.net/kml/2.2\" xmlns:gx=\"http://www.google.com/kml/ext/2.2\"" );
    ByteArrayInputStream bais = new ByteArrayInputStream( str.getBytes( "UTF-8" ) );
    return Kml.unmarshal(bais);
}
于 2014-09-26T14:57:56.617 回答
1

我对 Jak 不熟悉，但如果您使用的是OGC Schema，则命名空间是不同的。你有

http://earth.google.com/kml/2.2

OGC 命名空间是

http://www.opengis.net/kml/2.2

Google扩展架构使用

http://www.google.com/kml/ext/2.2

也是。在将 KML 作为开放标准提供给 OGC 之前，Google 使用了您使用的命名空间。

于 2012-02-08T19:41:30.093 回答
0

命名空间不正确，但如果您有 1700 个文件并且这是唯一的问题，您可以考虑简单地使用 Kml.unmarshal(File file, boolean validate) 的两个参数形式。

final Kml kml = loadXMLFile("../data/Eemskanaal.kml");
private static Kml loadXMLFile(String path) {
        Kml kml = null;
        try {
            kml = Kml.unmarshal(path);
        } catch (RuntimeException ex) {
            kml = Kml.unmarshal(new File(path), false);
        }
        return kml;
    }

我还使用了以下俗气的 perl 脚本来更正我的文件。

$ cat ~/bin/fixxmlns
#!/usr/bin/perl

for (@ARGV) {

    open (FH,"<$_");
    open (NFH,">$_.x");

    $look = 1;
    while ($r = <FH>) {
        if ($look && $r =~ /earth.google.com/) {
            $r = qq{<kml xmlns="http://www.opengis.net/kml/2.2" xmlns:atom="http://www.w3.org/2005/Atom" xmlns:gx="http://www.google.com/kml/ext/2.2">\n};
            $look = 0;
            }
        print NFH $r;
    }
    close (NFH);
    close (FH);
    rename("$_", "$_.orig");
    rename("$_.x", "$_");
}
$ fixxmlns *.kml
$ find parentdir -name "*.kml" -print0 | xargs -0 fixxmlns
于 2013-01-09T18:59:47.553 回答