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我正在阅读这篇文章, http: //mikehillyer.com/articles/managing-hierarchical-data-in-mysql/

我想举一个简单的例子,然后问你我如何得到想要的结果?所以这里是一个例子:

+---------+-----------------------------+
|  product_id | product_name            |
+---------+-----------------------------+
|           1 | Example Product         |
+---------+-----------------------------+
+---------+-----------------------------+
|  product_id | category_id             | 
+---------+-----------------------------+
|           1 | 2                       |
|           1 | 4                       |
+---------+-----------------------------+
+-------------+--------------------+------+------+
| category_id | name                 | lft | rgt |
+-------------+--------------------+------+------+
|           1 | Electronics          |  1  |  8  |
|           2 | Televisions          |  2  |  3  |
|           3 | Portable Electronics |  4  |  7  | 
|           4 | CD Players           |  5  |  6  |
+-------------+--------------------+------+------+

在查询并在 PHP 中操作数据后,我希望能够在 HTML 中显示以下结果:

"Example Product" Categories:
Electronics
    Televisions 
    Portable Electronics
        CD Players

您能帮我完成 PHP 中的查询和操作以实现此结果吗?

一些需要考虑的细节:

  1. 请注意这两个类别都在“电子”下,但“电子”在这里只出现一次,显示它所属的每个子类别
  2. 结果最终应该是一个 PHP 多维数组,其中类别包含一个子类别数组,每个子类别包含一个子子类别数组(如果存在)。

我想打印深度对于在 HTML 中构建正确的树非常重要。

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1 回答 1

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我认为这是一个很好的挑战..这是我的解决方案:

基本上:读取一个节点,然后所有rgt小于你的节点rgt都是你的孩子,递归地执行此操作。我像往常一样使用peek/consume从 mysql 中读取数据。

如果查询没有结果,或者数据集被破坏,脚本将中断或循环。

class NestedNodeReader {

    private $mysql_result;
    private $peeked = false;
    private $last_peek;

    public function __construct($mysql_result) {
        $this->mysql_result = $mysql_result;
    }

    public function getTree() {
        $root = $this->consume();
        $root["children"] = $this->getSubTree($root["rgt"]);
        return $root;
    }

    private function getSubTree($stop_at) {
        $nodes = array();
        $node = $this->peek();
        while ($node["rgt"] < $stop_at) {
            $node = $this->consume();
            $node["children"] = $this->getSubTree($node["rgt"]);
            $nodes[] = $node;
            $node = $this->peek();
            if (false === $node) {
                break;
            }
        }
        return $nodes;
    }

    private function peek() {
        if (false === $this->peeked) {
            $this->peeked = true;
            $this->last_peek = mysql_fetch_assoc($this->mysql_result);
        }
        return $this->last_peek;
    }

    private function consume() {
        if (false === $this->peeked) {
            return mysql_fetch_assoc($this->mysql_result);
        } else {
            $this->peeked = false;
            return $this->last_peek;
        }
    }
}

$query = "SELECT node.name, node.lft, node.rgt
    FROM nested_category AS node,
        nested_category AS parent
    WHERE node.lft BETWEEN parent.lft AND parent.rgt
        AND parent.name = 'ELECTRONICS'
    ORDER BY node.lft;"
$mysql_result = mysql_query($query);
$nnr = new NestedNodeReader($mysql_result);
print_r($nnr->getTree());
于 2012-02-07T22:42:42.780 回答