1

我正在尝试自动登录网页。我假设我通过了正确的凭据。

entity.getContentLength() 显示 20 但我看到的响应格式不正确。它不是 HTML。我应该如何进一步进行。下面是我的代码。

String input_text = "https://www.abc.com";
                HttpPost httpost = new HttpPost(input_text);

                List <NameValuePair> nvps = new ArrayList <NameValuePair>();
                nvps.add(new BasicNameValuePair("email", "abc@xyz.com"));
                nvps.add(new BasicNameValuePair("passsword", "ttyyeri"));   
                nvps.add(new BasicNameValuePair("publicLoginToken",""));

                httpost.setEntity(new UrlEncodedFormEntity(nvps, HTTP.UTF_8));

                HttpResponse  response = httpclient.execute(httpost);
                entity  = response.getEntity();

                if (entity != null) {
                  BufferedReader br = new BufferedReader(new InputStreamReader(entity.getContent()));
                  String readLine;
                  while(((readLine = br.readLine()) != null)) {
                    System.err.println("br   :"+readLine);
                 }
                  System.out.println("Response content length: " + entity.getContentLength());

                }      

                System.out.println("HTML Content :::"+entity.getContent().toString());
4

3 回答 3

1

尝试

  StatusLine l = response.getStatusLine();
  System.out.println(l.getStatusCode() + "  " + l .getReasonPhrase());

输出 ?

于 2012-02-07T21:42:37.600 回答
0

听起来您正在获得授权请求重定向。这可能已经在这里介绍过:Http Basic Authentication in Java using HttpClient?

于 2012-02-07T21:38:08.580 回答
0

调查 HttpResponse Header,可以找到内容类型和响应码。这将帮助您找到问题所在。

于 2012-02-07T21:42:52.283 回答